Prentice Hall Geometry

Proof Proof of Theorem 6-3

Given: white parallelogram eh b c d

Prove: eh b bar , approximately equal to , c d bar and b c bar , approximately equal to , d eh bar

Parallelogram ABCD is divided by diagonal AC, with angle 1 at BAC, angle 2 at DAB, angle 3 at BCA, and angle 4 at DCA.

Statements Reasons
1) ABCD is a parallelogram. 1) Given
2) eh b bar , parallel to , c d bar and b c bar , parallel to , d eh bar 2) Definition of parallelogram
3) angle , 1 approximately equal to , angle 4 and angle 3 approximately equal to angle 2 3) If lines are parallel to comma then alt. int. Angles. are approximately equal to .
4) eh c bar , approximately equal to , eh c bar 4) Reflexive Property of approximately equal to
5) cap delta eh b c approximately equal to cap delta c d eh 5) ASA
6) eh b bar , approximately equal to , c d bar and b c bar , approximately equal to , d eh bar 6) Corresp. parts of approximately equal to Triangles. are approximately equal to .

Angles of a polygon that share a side are consecutive angles. In the diagram, angle eh and angle b are consecutive angles because they share side eh b bar , .

Parallelogram ABCD has sides AB and CD parallel and sides AD and BC parallel. Angle B and angle C are also consecutive angles.

The theorem below uses the fact that consecutive angles of a parallelogram are same-side interior angles of parallel lines.


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Table of Contents

Prentice Hall Geometry Chapter 1 Tools of Geometry Chapter 2 Reasoning and Proof Chapter 3 Parallel and Perpendicular Lines Chapter 4 Congruent Triangles Chapter 5 Relationships Within Triangles Chapter 6 Polygons and Quadrilaterals Chapter 7 Similarity Chapter 8 Right Triangles and Trigonometry Chapter 9 Transformations Chapter 10 Area Chapter 11 Surface Area and Volume Chapter 12 Circles Skills Handbook Reference Visual Glossary Selected Answers Index Acknowledgments