-
Nautical Distance A close estimate of the radius of Earth's equator is 3960 mi.
- Write the equation of the equator with the center of Earth as the origin.
- Find the length of a
1
°
1 degrees arc on the equator to the nearest tenth of a mile.
-
History Columbus planned his trip to the East by going west. He thought each
1
°
1 degrees arc was 45 mi long. He estimated that the trip would take 21 days. Use your answer to part (b) to find a better estimate.
Standardized Test Prep
SAT/ACT
- What is an equation of a circle with radius 16 and center
(
2
,
−
5
)
?
open 2 comma negative 5 close question mark
-
(
x
−
2
)
2
+
(
y
+
5
)
2
=
16
open x minus . 2 , close squared , plus , open y plus . 5 , close squared . equals 16
-
(
x
+
2
)
2
+
(
y
−
5
)
2
=
4
open x plus . 2 , close squared , plus , open y minus . 5 , close squared . equals 4
-
(
x
+
2
)
2
+
(
y
−
5
)
2
=
256
open x plus . 2 , close squared , plus , open y minus . 5 , close squared . equals 256
-
(
x
−
2
)
2
+
(
y
+
5
)
2
=
256
open x minus . 2 , close squared , plus , open y plus . 5 , close squared . equals 256
-
What can you NOT conclude from the diagram below?
Image Long Description
-
c
=
d
c equals d
-
c
2
+
e
2
=
b
2
c squared , plus , e squared , equals , b squared
-
a
=
b
eh equals b
-
e
=
d
e equals d
Short Response
- Are the following statements equivalent?
- In a circle, if two central angles are congruent, then they have congruent arcs.
- In a circle, if two arcs are congruent, then they have congruent central angles.
Mixed Review
See Lesson 12-4.
Find the value of each variable.
-
-
See Lesson 8-5.
For the given vectors
a
⇀
modified a with right harpoon up above and
C
⇀
,
c with right harpoon up above , comma write the sum
a
⇀
+
C
⇀
modified a with right harpoon up above , plus , c with right harpoon up above as an ordered pair.
-
a
⇀
=
〈
−
2
,
5
〉
modified a with right harpoon up above , equals left pointing angle bracket negative 2 comma , 5 right pointing angle bracket and
C
⇀
=
〈
8
,
7
〉
c with right harpoon up above , equals left pointing angle bracket 8 comma 7 right pointing angle bracket
-
a
⇀
=
〈
−
3
,
−
4
〉
modified a with right harpoon up above , equals left pointing angle bracket negative 3 comma negative , 4 right pointing angle bracket and
C
⇀
=
〈
−
2
,
6
〉
c with right harpoon up above , equals left pointing angle bracket negative 2 comma 6 right pointing angle bracket
-
a
⇀
=
〈
3
,
1
〉
modified a with right harpoon up above , equals left pointing angle bracket 3 comma , 1 right pointing angle bracket and
C
⇀
=
〈
1
,
3
〉
c with right harpoon up above , equals left pointing angle bracket 1 comma 3 right pointing angle bracket
-
a
⇀
=
〈
9
,
−
6
〉
modified a with right harpoon up above , equals left pointing angle bracket 9 comma negative , 6 right pointing angle bracket and
C
⇀
=
〈
2
,
−
1
〉
c with right harpoon up above , equals , left pointing angle bracket 2 comma minus , 1 right pointing angle bracket
See Lessons 1-2 and 1-5.
Get Ready! To prepare for Lesson 12-6, do Exercises 69–71.
Sketch each of the following.
- the perpendicular bisector of
B
C
¯
b c bar
- line k parallel to line m and perpendicular to line w, all in plane N
-
∠
E
F
G
angle e f g bisected by
F
H
→
f h vector