Practice and Problem-Solving Exercises
A Practice
See Problem 1.
Write the standard equation of each circle.
- center
(
2
,
−
8
)
;
r
=
9
open 2 comma negative 8 close semicolon , r equals 9
- center
(
0
,
3
)
;
r
=
7
open 0 comma 3 close semicolon , r equals 7
- center
(
0.2
,
1.1
)
;
r
=
0
.
4
open 0.2 comma 1.1 close semicolon , r equals 0 . , 4
- center
(
5
,
−
1
)
;
r
=
12
open 5 comma negative 1 close semicolon , r equals 12
- center
(
−
6
,
3
)
;
r
=
8
open minus , 6 comma 3 close semicolon , r equals 8
- center
(
−
9
,
−
4
)
;
r
=
5
open minus , 9 comma negative 4 close semicolon , r equals , square root of 5
- center
(
0
,
0
)
;
r
=
4
open 0 comma 0 close semicolon , r equals 4
- center
(
−
4
,
0
)
;
r
=
3
open minus , 4 comma 0 close semicolon , r equals 3
- center
(
−
1
,
−
1
)
;
r
=
1
open minus , 1 comma negative 1 close semicolon , r equals 1
See Problem 2.
Write a standard equation for each circle in the diagram below.
Image Long Description
-
⊙
P
circle dot p
-
⊙
Q
circle dot q
Write the standard equation of the circle with the given center that passes through the given point.
- center
(
−
2
,
6
)
;
point
(
−
2
,
10
)
open minus , 2 comma 6 close semicolon , point . open minus , 2 comma 10 close
- center (1, 2); point (0, 6)
- center
(
7
,
−
2
)
;
point
(
1
,
−
6
)
open 7 comma negative 2 close semicolon , point , open 1 comma negative 6 close
- center
(
−
10
,
−
5
)
;
point
(
−
5
,
5
)
open minus , 10 comma negative 5 close semicolon , point . open minus , 5 comma 5 close
- center (6, 5); point (0, 0)
- center
(
−
1
,
−
4
)
;
point
(
−
4
,
0
)
open minus , 1 comma negative 4 close semicolon , point . open minus , 4 comma 0 close
See Problem 3.
Find the center and radius of each circle. Then graph the circle.
-
(
x
+
7
)
2
+
(
y
−
5
)
2
=
16
open x plus . 7 , close squared , plus , open y minus . 5 , close squared . equals 16
-
(
x
−
3
)
2
+
(
y
+
8
)
2
=
100
open x minus . 3 , close squared , plus , open y plus . 8 , close squared . equals 100
-
(
x
+
4
)
2
+
(
y
−
1
)
2
=
25
open x plus . 4 , close squared , plus , open y minus . 1 , close squared . equals 25
-
x
2
+
y
2
=
36
x squared , plus , y squared , equals 36
Public Safety Each equation models the position and range of a tornado alert siren. Describe the position and range of each.
-
(
x
−
5
)
2
+
(
y
−
7
)
2
=
81
open x minus . 5 , close squared , plus , open y minus . 7 , close squared . equals 81
-
(
x
+
4
)
2
+
(
y
−
9
)
2
=
144
open x plus . 4 , close squared , plus , open y minus . 9 , close squared . equals 144
B Apply
Write the standard equation of each circle.
-
-
-
-
-
-