-
- Graph
2
x
+
3
y
=
6
,
2
x
+
3
y
=
12
,
2 x plus 3 y equals 6 comma 2 x plus 3 y equals 12 comma and
2
x
+
3
y
=
18
2 x plus 3 y equals 18 in the same coordinate plane.
- How are the lines from part (a) related?
- As C increases, what happens to the graph of
2
x
+
3
y
=
C
?
2 x plus 3 y equals c question mark
-
-
Fundraising Suppose your school is having a talent show to raise money for new band supplies. You think that 200 students and 150 adults will attend. It will cost $200 to put on the talent show. What is an equation that describes the ticket prices you can set for students and adults to raise $1000?
-
Open-Ended Graph your equation. What are three possible prices you could set for student and adult tickets?
Standardized Test Prep
SAT/ACT
-
What is
y
=
−
3
4
x
+
2
y equals negative , 3 fourths , x plus 2 written in standard form using integers?
-
3
4
x
+
y
=
2
3 fourths , x plus y equals 2
-
3
x
+
4
y
=
2
3 x plus 4 y equals 2
-
3
x
+
4
y
=
8
3 x plus 4 y equals 8
-
−
3
x
−
4
y
=
8
negative 3 x minus 4 y equals 8
-
Which of the following is an equation of a horizontal line?
-
3
x
+
6
y
=
0
3 x plus 6 y equals 0
-
2
x
+
7
=
0
2 x plus 7 equals 0
-
−
3
y
=
29
negative 3 y equals 29
-
x
−
2
y
=
4
x minus 2 y equals 4
-
Which equation models a line with the same y-intercept but half the slope of the line
y
=
6
−
8
x
?
y equals 6 minus 8 x question mark
-
y
=
−
4
x
+
3
y equals negative 4 x plus 3
-
y
=
6
−
4
x
y equals 6 minus 4 x
-
y
=
3
−
8
x
y equals 3 minus 8 x
-
y
=
−
16
x
+
6
y equals negative 16 x plus 6
-
What is the solution of
7
2
x
−
19
=
−
13
+
2
x
?
7 halves , x minus 19 equals negative 13 plus 2 x question mark
-
−
9
negative 9
-
−
4
negative 4
- 4
- 9
Short Response
- The drama club plans to attend a professional production. Between 10 and 15 students will go. Each ticket costs $25 plus a $2 surcharge. There is a one-time handling fee of $3 for the entire order. What is a linear function that models this situation? What domain and range are reasonable for the function?
Mixed Review
See Lesson 5-4.
Write an equation in point-slope form of the line that passes through the given points. Then write the equation in slope-intercept form.
-
(
5
,
−
1
)
,
(
−
3
,
4
)
open 5 comma negative 1 close comma open negative 3 comma 4 close
-
(
0
,
−
2
)
,
(
3
,
2
)
open 0 comma negative 2 close comma open 3 comma 2 close
-
(
−
2
,
−
1
)
,
(
1
,
2
)
open negative 2 comma negative 1 close comma open 1 comma 2 close
See Lesson 3-6.
Solve each compound inequality. Graph your solution.
-
−
6
<
3
t
≤
9
negative 6 less than 3 t less than or equal to 9
-
−
9.5
<
3
−
y
≤
1.3
negative 9.5 less than 3 minus y less than or equal to 1.3
-
3
x
+
1
>
10
or
5
x
+
3
≤
−
2
3 x plus 1 greater than 10 , or , 5 x plus 3 less than or equal to negative 2
Get Ready! To prepare for Lesson 5-6, do Exercises 77–79.
See Lesson 5-1.
Find the slope of the line that passes through each pair of points.
- (0,
−
4
negative 4 ), (2, 0)
- (5, 5), (3,
−
1
negative 1 )
- (
−
4
,
negative 4 comma 2), (5, 2)