-
- Use the property for dividing powers with the same base to write
a
0
a
n
fraction eh to the , over eh to the n end fraction as a power of a.
- Use the definition of a zero exponent to simplify
a
0
a
n
.
fraction eh to the , over eh to the n end fraction . .
-
Reasoning Explain how your results from parts (a) and (b) justify the definition of a negative exponent.
C Challenge
-
Reasoning Use the division property to show why
0
0
0 to the is undefined.
Simplify each expression.
-
n
x
+
2
÷
n
x
n super x plus 2 end super . divides , n to the x
-
n
5
x
÷
n
x
n to the fifth , to the x , divides , n to the x
-
(
x
n
x
n
−
2
)
3
open . fraction x to the n , over x super n minus 2 end super end fraction . close cubed
-
(
m
4
m
5
)
m
2
fraction open . fraction m to the fourth , over m to the fifth end fraction . close , over m squared end fraction
-
Astronomy The density of an object is the ratio of its mass to its volume. Neptune has a mass of
1.02
×
10
26
1.02 , times , 10 to the twenty sixth kg. The radius of Neptune is
2.48
×
10
4
2.48 , times , 10 to the fourth km. What is the density of Neptune in grams per cubic meter? (Hint:
V
=
4
3
π
r
3
v equals , 4 thirds , pi , r cubed )
Standardized Test Prep
SAT/ACT
-
Which expression is equivalent to
(
2
x
)
5
x
3
?
fraction open , 2 x , close to the fifth , over x cubed end fraction . question mark
-
2
x
2
2 , x squared
-
32
x
2
32 , x squared
-
2
x
8
2 , x to the eighth
-
32
x
−
2
32 , x super negative 2 end super
-
Which equation is an equation of the line that contains the point (8,
–
3
en dash 3 ) and is perpendicular to the line
y
=
–
4
x
+
5
?
y equals en dash 4 x plus 5 question mark
-
y
=
−
1
4
x
−
1
y equals negative , 1 fourth , x minus 1
-
y
=
1
4
x
+
35
4
y equals , 1 fourth , x plus , 35 over 4
-
y
=
1
4
x
−
5
y equals , 1 fourth , x minus 5
-
y
=
4
x
−
35
y equals 4 x minus 35
-
What is the solution of the system of equations
y
=
–
3
x
+
5
y equals en dash 3 x plus 5 and
y
=
–
4
x
–
1
?
y equals en dash 4 x en dash 1 question mark
- (23, 6)
- (6, 23)
-
(
−
6
,
23
)
open negative 6 comma 23 close
-
(
−
6
,
−
23
)
open negative 6 comma negative 23 close
-
Short Response 97. You have 8 bags of grass seed. Each bag covers
1200
ft
2
1200 , ft squared of ground. The function
A
(
b
)
=
1200
b
eh open b close equals , 1200 , b represents the area
A
(
b
)
,
eh open b close comma in square feet, that b bags cover. What domain and range are reasonable for the function? Explain.
Mixed Review
See Lesson 7-4.
Simplify each expression.
-
(
2
m
−
7
)
3
open 2 , m to the minus , to the seventh , close cubed
-
2
(
3
s
−
2
)
−
3
2 . open . 3 , s super negative 2 end super . close super negative 3 end super
-
(
4
3
c
2
)
−
1
open . 4 cubed , c squared . close super negative 1 end super
-
(
−
3
)
2
(
r
5
)
2
open , negative 3 , close squared . open , r to the fifth , close squared
-
(
7
0
n
−
3
)
2
(
n
7
)
3
open . 7 to the . n super negative 3 end super . close squared . open , n to the seventh , close cubed
See Lesson 6-1.
Solve each system by graphing.
-
y
=
3
x
y
=
−
2
x
table with 2 rows and 1 column , row1 column 1 , y equals 3 x , row2 column 1 , y equals negative 2 x , end table
-
y
=
2
x
+
1
y
=
x
−
3
table with 2 rows and 1 column , row1 column 1 , y equals 2 x plus 1 , row2 column 1 , y equals x minus 3 , end table
-
y
=
5
x
=
3
table with 2 rows and 1 column , row1 column 1 , y equals 5 , row2 column 1 , x equals 3 , end table
-
y
=
7
y
=
8
table with 2 rows and 1 column , row1 column 1 , y equals 7 , row2 column 1 , y equals 8 , end table
Get Ready! To prepare for Lesson 7-6, do Exercises 107–110.
See Lesson 4-4.
Graph each function.
-
y
=
4
x
y equals 4 x
-
y
=
5
x
y equals 5 x
-
y
=
−
3
x
y equals negative 3 x
-
y
=
1.5
x
y equals 1.5 x