Concept Byte: Dividing Polynomials Using Algebra Tiles
Use With Lesson 11-3
ACTIVITY
You can use algebra tiles to model polynomial division.
Activity
What is
(
x
2
+
4
x
+
3
)
÷
(
x
+
3
)
?
open , x squared , plus 4 x plus 3 close divides open x plus 3 close question mark Use algebra tiles.
-
Step 1 Use algebra tiles to model the dividend,
x
2
+
4
x
+
3
.
x squared , plus 4 x plus 3 .
-
Step 2 Use the
x
2
x squared -tile and the 1-tiles to form a figure with length
x
+
3
,
x plus 3 comma the divisor.
-
Step 3 Use the remaining tiles to fill in the rectangle.
Since
(
x
+
1
)
(
x
+
3
)
=
x
2
+
4
x
+
3
,
open x plus 1 close open x plus 3 close equals , x squared , plus 4 x plus 3 comma you can write
(
x
2
+
4
x
+
3
)
÷
(
x
+
3
)
=
x
+
1
.
open , x squared , plus 4 x plus 3 close divides open x plus 3 close equals x plus 1 .
Check Check your result by multiplying
x
+
1
x plus 1 and
x
+
3
.
x plus 3 . The product should be the dividend,
x
2
+
4
x
+
3
.
x squared , plus 4 x plus 3 .
(
x
+
1
)
(
x
+
3
)
=
(
x
)
(
x
)
+
(
x
)
(
3
)
+
(
1
)
(
x
)
+
(
1
)
(
3
)
=
x
2
+
3
x
+
x
+
3
=
x
2
+
4
x
+
3
✓
table with 3 rows and 2 columns , row1 column 1 , open , x plus 1 , close . open , x plus 3 , close , column 2 equals , open x close . open x close , plus , open x close . open 3 close , plus , open 1 close . open x close , plus , open 1 close . open 3 close , row2 column 1 , , column 2 equals , x squared , plus 3 x plus x plus 3 , row3 column 1 , , column 2 equals , x squared , plus 4 x plus 3 check mark , end table
Exercises
Use algebra tiles to find each quotient. Check your result.
-
(
x
2
+
6
x
+
8
)
÷
(
x
+
4
)
open , x squared , plus 6 x plus 8 close divides open x plus 4 close
-
(
x
2
+
5
x
+
6
)
÷
(
x
+
2
)
open , x squared , plus 5 x plus 6 close divides open x plus 2 close
-
(
x
2
+
8
x
+
12
)
÷
(
x
+
6
)
open , x squared , plus 8 x plus 12 close divides open x plus 6 close
-
(
x
2
+
8
x
+
7
)
÷
(
x
+
1
)
open , x squared , plus 8 x plus 7 close divides open x plus 1 close
-
Reasoning In Exercises 1–4, the divisor is a factor of the dividend. How do you know? Can you use algebra tiles to represent polynomial division when the divisor is not a factor of the dividend? Explain.