C Challenge
-
Geometry A square has sides with length n. How much must be added to the length of one side to transform the square into a golden rectangle?
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Reasoning What are three fractions that you can multiply
1
2
+
3
fraction 1 , over square root of 2 plus 3 end fraction by to rationalize the denominator? Will the resulting products be the same? Explain.
-
Geometry Find the length of each hypotenuse. Write your answer in simplified radical form.
-
-
-
Standardized Test Prep
SAT/ACT
- What is the simplified form of
2
18
−
32
+
4
8
?
2 square root of 18 minus square root of 32 plus 4 square root of 8 question mark
-
8
3
8 square root of 3
-
10
2
10 square root of 2
-
18
2
18 square root of 2
-
10
18
10 , square root of 18
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A surveyor is calculating the areas of lots that are going to be sold.
The dimensions of one lot are shown below. What is the area of the lot shown?
-
8.82
×
10
6
m
2
8.82 , times , 10 to the sixth , , m squared
-
8.82
×
10
5
m
2
8.82 , times , 10 to the fifth , , m squared
-
4.41
×
10
5
m
2
4.41 , times , 10 to the fifth , , m squared
-
4.41
×
10
6
m
2
4.41 , times , 10 to the sixth , , m squared
-
What are the approximate solutions of the equation
5
2
x
2
+
3
4
x
−
5
=
0
?
5 halves , x squared , plus , 3 fourths , x minus 5 equals 0 question mark
Use a graphing calculator.
-
−
5
,
0
negative 5 comma 0
-
−
1.57
,
1.27
negative , 1.57 , comma , 1.27
-
−
1.36
,
0.71
negative , 1.36 , comma , 0.71
-
−
0.96
,
0.84
negative , 0.96 , comma , 0.84
-
Short Response What are the domain and range of the function
y
=
|
x
|
?
y equals absolute value of x , , question mark Show how you find your answer.
Mixed Review
See Lesson 10-2.
Simplify each radical expression.
-
108
square root of 108
-
3
150
3 , square root of 150
-
4
18
c
2
fraction 4 , over square root of 18 , c squared end root end fraction
-
5
·
45
square root of 5 middle dot square root of 45
See Lesson 7-3.
Rewrite each expression using each base only once.
-
8
5
·
8
11
8 to the fifth , middle dot , 8 to the eleventh
-
2
24
·
2
−
13
2 to the twenty fourth , middle dot , 2 super negative 13 end super
-
5
11
·
5
16
5 to the eleventh , middle dot , 5 to the sixteenth
-
3
7
·
3
−
4
3 to the seventh , middle dot , 3 super negative 4 end super
Get Ready! To prepare for Lesson 10-4, do Exercises 76–81.
See Lesson 9-4.
Solve by factoring.
-
x
2
+
2
x
+
1
=
0
x squared , plus 2 x plus 1 equals 0
-
x
2
+
x
−
12
=
0
x squared , plus x minus 12 equals 0
-
x
2
+
2
x
−
15
=
0
x squared , plus 2 x minus 15 equals 0
-
3
x
2
+
7
x
−
6
=
0
3 , x squared , plus 7 x minus 6 equals 0
-
2
x
2
+
3
x
−
2
=
0
2 , x squared , plus 3 x minus 2 equals 0
-
x
2
+
14
x
+
49
=
0
x squared , plus 14 x plus 49 equals 0