Practice and Problem-Solving Exercises
A Practice
See Problem 1.
Find the value of c such that each expression is a perfect-square trinomial.
-
x
2
+
18
x
+
c
x squared , plus 18 . x plus c
-
z
2
+
22
z
+
c
z squared , plus 22 . z plus c
-
p
2
−
30
p
+
c
p squared , minus 30 . p plus c
-
k
2
−
5
k
+
c
k squared , minus 5 . k plus c
-
g
2
+
17
g
+
c
g squared , plus 17 . g plus c
-
q
2
−
4
q
+
c
q squared , minus 4 . q plus c
See Problems 2 and 3.
Solve each equation by completing the square. If necessary, round to the nearest hundredth.
-
g
2
+
7
g
=
144
g squared , plus 7 . g equals 144
-
r
2
−
4
r
=
30
r squared , minus 4 . r equals 30
-
m
2
+
16
m
=
−
59
m squared , plus 16 . m equals negative 59
-
q
2
+
4
q
=
16
q squared , plus 4 . q equals 16
-
x
2
+
18
x
=
307
x squared , plus 18 . x equals 307
-
z
2
−
2
z
=
323
z squared , minus 2 . z equals 323
-
a
2
−
2
a
−
35
=
0
eh squared , minus 2 . eh minus 35 equals 0
-
m
2
+
12
m
+
19
=
0
m squared , plus 12 . m plus 19 equals 0
-
w
2
−
14
w
+
13
=
0
w squared , minus 14 . w plus 13 equals 0
-
p
2
+
5
p
−
7
=
0
p squared , plus 5 . p minus 7 equals 0
-
t
2
+
t
−
28
=
0
t squared , plus , t minus 28 equals 0
-
g
2
+
11
g
−
468
=
0
g squared , plus 11 . g minus 468 equals 0
See Problem 4.
Solve each equation by completing the square. If necessary, round to the nearest hundredth.
-
4
a
2
−
8
a
=
24
4 eh squared , minus 8 eh equals 24
-
2
y
2
−
8
y
−
10
=
0
2 y squared , minus 8 y minus 10 equals 0
-
5
n
2
−
3
n
−
15
=
10
5 n squared , minus 3 n minus 15 equals 10
-
4
w
2
+
12
w
−
44
=
0
4 w squared , plus 12 w minus 44 equals 0
-
3
r
2
+
18
r
=
21
3 r squared , plus 18 r equals 21
-
2
v
2
−
10
v
−
20
=
8
2 v squared , minus 10 v minus 20 equals 8
-
Art The painting shown below has an area of
420
in.
2
.
420 . in. squared , . What is the value of x?