C Challenge
Factor by grouping.
-
y
3
+
11
y
2
−
4
y
−
44
y cubed , plus , 11 y squared , minus 4 y minus 44
-
p
2
m
+
p
2
n
5
+
q
m
+
qn
5
p squared , m plus , p squared , n to the fifth , plus q m plus , qn to the fifth
-
30
g
5
+
24
g
3
h
−
35
g
2
h
2
−
28
h
3
30 g to the fifth , plus , 24 g cubed , h minus , 35 g squared . h squared , minus , 28 h cubed
-
Geometry The polynomial
2
π
x
3
+
12
π
x
2
+
18
π
x
2 pi , x cubed , plus 12 pi , x squared , plus 18 pi x represents the volume of a cylinder. The formula for the volume V of a cylinder with radius r and height h is
V
=
π
r
2
h
.
v equals pi , r squared , h .
- Factor
2
π
x
3
+
12
π
x
2
+
18
π
x
.
2 pi , x cubed , plus 12 pi , x squared , plus 18 pi x .
- Based on your answer to part (a), write an expression for a possible radius of the cylinder.
You can write the number 63 as
2
5
+
2
4
+
2
3
+
2
2
+
2
1
+
2
0
.
2 to the fifth , plus , 2 to the fourth , plus , 2 cubed , plus , 2 squared , plus , 2 to the first , plus , 2 to the , . For Exercises 45 and 46, factor each expression by grouping. Then simplify the powers of 2 to write 63 as the product of two numbers.
-
(
2
5
+
2
4
+
2
3
)
+
(
2
2
+
2
1
+
2
0
)
open , 2 to the fifth , plus , 2 to the fourth , plus , 2 cubed , close plus open , 2 squared , plus , 2 to the first , plus , 2 to the , close
-
(
2
5
+
2
4
)
+
(
2
3
+
2
2
)
+
(
2
1
+
2
0
)
open , 2 to the fifth , plus , 2 to the fourth , close plus open , 2 cubed , plus , 2 squared , close plus open , 2 to the first , plus , 2 to the , close
Standardized Test Prep
SAT/ACT
-
What is
30
z
3
−
12
z
2
+
120
z
−
48
30 z cubed , minus , 12 z squared , plus 120 z minus 48 factored completely?
-
2
(
15
z
3
−
6
z
2
+
60
z
−
24
)
2 open , 15 z cubed , minus , 6 z squared , plus 60 z minus 24 close
-
(
6
z
2
+
24
)
(
5
z
−
2
)
open , 6 z squared , plus 24 close open 5 z minus 2 close
-
6
(
5
z
3
−
2
z
2
+
20
z
−
8
)
6 open , 5 z cubed , minus , 2 z squared , plus 20 z minus 8 close
-
6
(
z
2
+
4
)
(
5
z
−
2
)
6 open , z squared , plus 4 close open 5 z minus 2 close
-
What is the simplified form of
2
x
3
·
x
8
?
2 x cubed , middle dot , x to the eighth , question mark
-
2
x
11
2 x to the eleventh
-
8
x
11
8 x to the eleventh
-
2
x
24
2 x to the twenty fourth
-
8
x
24
8 x to the twenty fourth
-
Which equation represents the line with slope
−
3
negative 3 that passes through (2, 5)?
-
y
=
−
3
x
+
17
y equals negative 3 x plus 17
-
y
=
−
3
x
+
11
y equals negative 3 x plus 11
-
y
=
4
x
−
3
y equals 4 x minus 3
-
y
=
x
−
3
y equals x minus 3
-
What is the solution of the inequality
7
<
−
2
x
+
5
?
7 less than negative 2 x plus 5 question mark
-
x
>
−
1
x greater than negative 1
-
x
<
−
1
x less than negative 1
-
x
>
1
x greater than 1
-
x
<
1
x less than 1
-
Short Response Factor
10
r
4
+
30
r
3
+
5
r
2
+
15
r
10 r to the fourth , plus , 30 r cubed , plus , 5 r squared , plus 15 r completely. Show your work.
Mixed Review
See Lesson 8-7.
Factor each expression.
-
m
2
+
12
m
+
36
m squared , plus 12 m plus 36
-
64
x
2
−
144
x
+
81
64 x squared , minus 144 x plus 81
-
49
p
2
−
4
49 p squared , minus 4
See Lesson 4-6.
Use a mapping diagram to determine whether each relation is a function.
- {(4, 3), (3, 4), (4, 7), (7, 4)}
- {(
−
1
,
negative 1 comma 8), (1, 8), (3, 8), (5, 8)}
- {(2, 7), (4,
−
7
negative 7 ), (6, 7), (8,
−
7
negative 7 )}
Get Ready! To prepare for Lesson 9-1, do Exercises 58–61.
See Lesson 5-3.
Use the slope and y-intercept to graph each equation.
-
y
=
1
2
x
+
3
y equals , 1 half , x plus 3
-
y
=
−
4
x
−
1
y equals negative 4 x minus 1
-
y
=
2
x
−
3
y equals 2 x minus 3
-
y
=
−
5
3
x
+
2
y equals negative , 5 thirds , x plus 2