See Problems 4 and 5.
Tell which solutions, if any, are extraneous for each equation.
-
−
z
=
−
z
+
6
;
z
=
−
3
,
z
=
2
negative z equals . square root of negative z plus 6 end root . semicolon z equals negative 3 comma z equals 2
-
12
−
n
=
n
;
n
=
−
4
,
n
=
3
square root of 12 minus n end root , equals n semicolon n equals negative 4 comma n equals 3
-
y
=
2
y
;
y
=
0
,
y
=
2
y equals , square root of 2 y end root , semicolon y equals 0 comma y equals 2
-
2
a
=
4
a
+
3
;
a
=
3
2
,
a
=
−
1
2
2 eh equals . square root of 4 eh plus 3 end root . semicolon eh equals , 3 halves , comma eh equals negative , 1 half
-
x
=
28
−
3
x
;
x
=
4
,
x
=
−
7
x equals . square root of 28 minus 3 x end root . semicolon x equals 4 comma x equals negative 7
-
−
t
=
−
6
t
−
5
;
t
=
−
5
,
t
=
−
1
negative t equals . square root of negative 6 t minus 5 end root . semicolon t equals negative 5 comma t equals negative 1
Solve each radical equation. Check your solution. If there is no solution, write no solution.
-
x
=
2
x
+
3
x equals . square root of 2 x plus 3 end root
-
n
=
4
n
+
5
n equals . square root of 4 n plus 5 end root
-
3
b
=
−
3
square root of 3 b end root , equals negative 3
-
2
y
=
5
y
+
6
2 y equals . square root of 5 y plus 6 end root
-
−
2
2
r
+
5
=
6
negative 2 . square root of 2 r plus 5 end root . equals 6
-
d
+
12
=
d
square root of d plus 12 end root , equals d
B Apply
-
Error Analysis A student solved the equation
r
=
−
6
r
−
5
r equals . square root of negative 6 r minus 5 end root and found the solutions
−
1
negative 1 and
−
5
.
negative 5 . Describe and correct the student's error.
-
Think About a Plan The total surface area A of Earth, in square kilometers, is related to Earth's radius r, in kilometers, by
r
=
A
4
π
.
r equals , square root of fraction eh , over 4 pi end fraction end root , . Earth's radius is about 6378 km. What is its surface area? Round to the nearest square kilometer.
- What equation in one variable can you solve to find Earth's surface area?
- How can you check the reasonableness of your solution?
-
Geometry In the right triangle
Δ
A
B
C
,
cap delta eh b c comma the altitude
C
D
¯
c d bar is at a right angle to the hypotenuse. You can use
C
D
=
(
A
D
)
(
D
B
)
c d equals . square root of open , eh d , close . open , d b , close end root to find missing lengths.
- Find AD if CD = 10 and DB = 4.
- Find DB if AD = 20 and CD = 15.
-
Packaging The radius r of a cylindrical can with volume V and height h is given by
r
=
V
π
h
.
r equals , square root of fraction v , over pi h end fraction end root , . What is the height of a can with a radius of 2 in. and a volume of
75
in
.
3
?
75 , in , . cubed , question mark
-
Writing Explain how you would solve the equation
2
y
−
y
+
2
=
0.
square root of 2 y end root , minus , square root of y plus 2 end root , equals 0.
-
Open-Ended Write two radical equations that have 3 for a solution.
Solve each radical equation. Check your solution. If there is no solution, write no solution.
-
5
x
+
10
=
5
square root of 5 x plus 10 end root . equals 5
-
−
6
−
3
y
=
−
3
negative 6 minus , square root of 3 y end root , equals negative 3
-
7
p
+
5
=
p
−
3
square root of 7 p plus 5 end root . equals , square root of p minus 3 end root
-
a
=
7
a
−
6
eh equals . square root of 7 eh minus 6 end root
-
y
+
12
=
3
y
square root of y plus 12 end root , equals 3 square root of y
-
3
−
4
a
+
1
=
12
3 minus . square root of 4 eh plus 1 end root . equals 12
-
Physics The formula
t
=
n
16
t equals , square root of n over 16 end root gives the time t in seconds for an object that is initially at rest to fall n feet. What is the distance an object falls in the first 10 s?