Standardized Test Prep
SAT/ACT
-
Which system of inequalities is shown in the graph?
-
{
x
≥
4
3
x
−
2
y
>
5
left brace . table with 2 rows and 1 column , row1 column 1 , x greater than or equal to 4 , row2 column 1 , 3 x minus 2 y greater than 5 , end table
-
{
x
>
4
3
x
−
2
y
≤
5
left brace . table with 2 rows and 1 column , row1 column 1 , x greater than 4 , row2 column 1 , 3 x minus 2 y less than or equal to 5 , end table
-
{
x
<
4
3
x
−
2
y
≥
5
left brace . table with 2 rows and 1 column , row1 column 1 , x less than 4 , row2 column 1 , 3 x minus 2 y greater than or equal to 5 , end table
-
{
x
≤
4
3
x
−
2
y
<
5
left brace . table with 2 rows and 1 column , row1 column 1 , x less than or equal to 4 , row2 column 1 , 3 x minus 2 y less than 5 , end table
- What is the equation of the line that passes through the point
(
4
,
−
3
)
open 4 comma negative 3 close and has slope
1
2
?
1 half , question mark
-
y
=
1
2
x
+
3
y equals , 1 half , x plus 3
-
y
=
1
2
x
−
1
y equals , 1 half , x minus 1
-
y
=
1
2
x
−
5
y equals , 1 half , x minus 5
-
y
=
x
−
1
2
y equals x minus , 1 half
- Which equation is a vertical translation of
y
=
−
5
x
?
y equals negative 5 x question mark
-
y
=
−
5
2
x
y equals negative , 5 halves , x
-
y
=
−
5
x
+
2
y equals negative 5 x plus 2
-
y
=
−
10
x
y equals negative 10 x
-
y
=
5
x
−
2
y equals 5 x minus 2
Short Response
- The cost of renting a pool at an aquatic center is either $30 per hour or $20 per hour with a $40 non-refundable deposit. For how many hours is the cost of renting a pool the same for both plans?
Mixed Review
See Lesson 3-2.
Solve each system by elimination or substitution.
-
{
y
=
3
x
+
1
2
x
−
y
=
8
left brace . table with 2 rows and 1 column , row1 column 1 , y equals 3 x plus 1 , row2 column 1 , 2 x minus y equals 8 , end table
-
{
3
x
+
y
=
4
2
x
−
4
y
=
7
left brace . table with 2 rows and 1 column , row1 column 1 , 3 x plus y equals 4 , row2 column 1 , 2 x minus 4 y equals 7 , end table
-
{
−
x
+
5
y
=
3
2
x
−
10
y
=
4
left brace . table with 2 rows and 1 column , row1 column 1 , negative x plus 5 y equals 3 , row2 column 1 , 2 x minus 10 y equals 4 , end table
-
{
2
x
+
4
y
=
−
8
−
5
x
+
4
y
=
6
left brace . table with 2 rows and 1 column , row1 column 1 , 2 x plus 4 y equals negative 8 , row2 column 1 , negative 5 x plus 4 y equals 6 , end table
-
{
y
−
3
=
x
4
x
+
y
=
−
2
left brace . table with 2 rows and 1 column , row1 column 1 , y minus 3 equals x , row2 column 1 , 4 x plus y equals negative 2 , end table
-
{
2
=
4
y
−
3
x
5
x
=
2
y
−
3
left brace . table with 2 rows and 1 column , row1 column 1 , 2 equals 4 y minus 3 x , row2 column 1 , 5 x equals 2 y minus 3 , end table
Get Ready! To prepare for Lesson 3-4, do Exercises 69–72.
See Lesson 3-3.
Write an ordered pair that is a solution of each system of inequalities.
-
{
x
+
y
>
2
3
x
+
2
y
≤
6
left brace . table with 2 rows and 1 column , row1 column 1 , x plus y greater than 2 , row2 column 1 , 3 x plus 2 y less than or equal to 6 , end table
-
{
2
y
>
4
3
x
+
4
y
≤
14
left brace . table with 2 rows and 1 column , row1 column 1 , 2 y greater than 4 , row2 column 1 , 3 x plus 4 y less than or equal to 14 , end table
-
{
x
≥
2
5
x
+
2
y
≤
9
left brace . table with 2 rows and 1 column , row1 column 1 , x greater than or equal to 2 , row2 column 1 , 5 x plus 2 y less than or equal to 9 , end table
-
{
x
+
3
y
<
6
y
<
x
left brace . table with 2 rows and 1 column , row1 column 1 , x plus 3 y less than 6 , row2 column 1 , y less than x , end table