C Challenge
- Show that the product of any complex number a + bi and its complex conjugate is a real number.
- For what real values of x and y is
(
x
+
y
i
)
2
open x plus y i , close squared an imaginary number?
-
Reasoning True or false: The conjugate of the additive inverse of a complex number is equal to the additive inverse of the conjugate of that complex number. Explain your answer.
Standardized Test Prep
SAT/ACT
- How can you rewrite the expression
(
8
−
5
i
)
2
open 8 minus 5 i , close squared in the form a + bi?
- 39 + 80 i
-
39
−
80
i
39 minus 80 i
- 69 + 80 i
-
69
−
80
i
69 minus 80 i
- How many solutions does the quadratic equation
4
x
2
−
12
x
+
9
=
0
4 x squared , minus 12 x plus 9 equals 0 have?
- two real solutions
- one real solution
- two imaginary solutions
- one imaginary solution
- What are the solutions of
3
x
2
−
2
x
−
4
=
0
?
3 x squared , minus 2 x minus 4 equals 0 question mark
-
1
±
13
3
fraction 1 plus minus square root of 13 , over 3 end fraction
-
1
±
i
11
3
fraction 1 plus minus i square root of 11 , over 3 end fraction
-
−
1
±
13
3
fraction negative 1 plus minus square root of 13 , over 3 end fraction
-
−
1
±
i
11
3
fraction negative 1 plus minus i square root of 11 , over 3 end fraction
Short Response
- Using factoring, what are all four solutions to
x
4
−
16
=
0
?
x to the fourth , minus 16 equals 0 question mark Show your work.
Mixed Review
See Lesson 4-7.
Solve each equation using the Quadratic Formula.
-
2
x
2
+
3
x
−
4
=
0
2 x squared , plus 3 x minus 4 equals 0
-
4
x
2
+
x
=
1
4 x squared , plus x equals 1
-
x
2
=
−
7
x
−
8
x squared , equals negative 7 x minus 8
See Lesson 4-1.
Graph each function. Identify the axis of symmetry.
-
y
=
−
2
(
x
+
1
)
2
−
3
y equals negative 2 open x plus 1 , close squared , minus 3
-
y
=
1
2
(
x
−
4
)
2
+
1
y equals , 1 half , open x minus 4 , close squared , plus 1
-
y
=
3
(
x
−
1
)
2
−
5
y equals 3 open x minus 1 , close squared , minus 5
See Lesson 2-3.
Write an equation for each line.
-
m
=
3
m equals 3 and the y-intercept is
−
4
negative 4
-
m
=
−
0
.
5
m equals negative 0 . 5 and the y-intercept is
−
2
negative 2
-
m
=
−
7
m equals negative 7 and the y-intercept is 10
-
m
=
2
m equals 2 and the y-intercept is 8
Get Ready! To prepare for Lesson 4-9, do Exercises 87–89.
See Lesson 3-3.
Solve each system of inequalities by graphing.
-
{
y
<
2
x
+
4
y
≥
|
x
−
3
|
+
2
left brace . table with 2 rows and 1 column , row1 column 1 , y less than 2 x plus 4 , row2 column 1 , y greater than or equal to absolute value of , x minus 3 , end absolute value , . plus 2 , end table
-
{
y
>
−
x
y
<
−
|
x
+
1
|
left brace . table with 2 rows and 1 column , row1 column 1 , y greater than negative x , row2 column 1 , y less than negative absolute value of , x plus 1 , end absolute value , , end table
-
{
y
≤
|
x
|
+
2
y
≥
−
1
2
x
+
4
left brace . table with 2 rows and 1 column , row1 column 1 , y less than or equal to absolute value of x , , plus 2 , row2 column 1 , y greater than or equal to negative , 1 half , x plus 4 , end table