C Challenge
Solve for x in terms of a
.
-
2
x
2
−
a
x
=
6
a
2
2 x squared , minus eh x equals , 6 eh squared
-
3
x
2
+
a
x
=
a
2
3 x squared , plus eh x equals , eh squared
-
2
a
2
x
2
−
8
a
x
=
−
6
2 , eh squared , x squared , minus 8 eh x equals negative 6
-
4
a
2
x
2
+
8
a
x
+
3
=
0
4 , eh squared , x squared , plus 8 eh x plus 3 equals 0
-
3
x
2
+
a
x
2
=
9
x
+
9
a
3 x squared , plus eh , x squared , equals 9 x plus 9 eh
-
6
a
2
x
2
−
11
a
x
=
10
6 , eh squared , x squared , minus 11 eh x equals 10
- Solve
x
2
=
(
6
2
)
x
+
7
x squared , equals open 6 square root of 2 close x plus 7 by completing the square.
Rewrite each equation in vertex form. Then find the vertex of the graph.
-
y
=
−
4
x
2
−
5
x
+
3
y equals negative 4 , x squared , minus 5 x plus 3
-
y
=
1
2
x
2
−
5
x
+
12
y equals , 1 half , x squared , minus 5 x plus 12
-
y
=
−
1
5
x
2
+
4
5
x
+
11
5
y equals negative , 1 fifth , x squared , plus , 4 fifths , x plus , 11 over 5
Standardized Test Prep
SAT/ACT
- The graph of which inequality has its vertex at
(
2
1
2
,
−
5
)
?
open . 2 , and 1 half , comma negative 5 . close . question mark
-
y
<
|
2
x
−
5
|
+
5
y less than , vertical line 2 x minus 5 vertical line plus 5
-
y
<
|
2
x
+
5
|
−
5
y less than , vertical line 2 x plus 5 vertical line negative 5
-
y
>
|
2
x
+
5
|
−
5
y greater than , vertical line 2 x plus 5 vertical line negative 5
-
y
>
|
2
x
−
5
|
−
5
y greater than , vertical line 2 x minus 5 vertical line negative 5
- Which number is a solution of
|
9
−
x
|
=
9
+
x
?
vertical line 9 minus x vertical line equals 9 plus x question mark
-
−
3
negative 3
- 0
- 3
- 6
- Joanne tosses an apple seed on the ground. It travels along a parabola with the equation
y
=
−
x
2
+
4
.
y equals negative , x squared , plus 4 . Assume the seed was thrown from a height of 4 ft. How many feet away from Joanne will the apple seed land?
- 1 ft
- 2 ft
- 4 ft
- 8 ft
Extended Response
- List the steps for solving the equation
x
2
−
9
=
−
8
x
x squared , minus 9 equals negative 8 x by the completing the square method. Explain each step.
Mixed Review
See Problem 4-5.
Solve each equation by factoring. Check your answers.
-
2
x
2
−
3
x
+
1
=
0
2 x squared , minus 3 x plus 1 equals 0
-
x
2
−
4
=
−
3
x
x squared , minus 4 equals negative 3 x
-
16
+
22
x
=
3
x
2
16 plus 22 x equals , 3 x squared
See Problem 4-3.
Determine whether a quadratic model exists for each set of values. If so, write the model.
-
(
−
4
,
3
)
,
(
−
3
,
3
)
,
(
−
2
,
4
)
open negative 4 comma 3 close comma open negative 3 comma 3 close comma open negative 2 comma 4 close
-
(
−
1
,
1
2
)
,
(
0
,
2
)
,
(
2
,
2
)
open . negative 1 comma , 1 half . close . comma . open , 0 comma 2 , close . comma . open , 2 comma 2 , close
-
(
0
,
2
)
,
(
1
,
0
)
,
(
2
,
4
)
open 0 comma 2 close comma open 1 comma 0 close comma open 2 comma 4 close
See Problem 3-2.
Solve each system by elimination.
-
{
2
x
+
y
=
4
3
x
−
y
=
6
left brace . table with 2 rows and 1 column , row1 column 1 , 2 x plus y equals 4 , row2 column 1 , 3 x minus y equals 6 , end table
-
{
2
x
+
y
=
7
−
2
x
+
5
y
=
−
1
left brace . table with 2 rows and 2 columns , row1 column 1 , 2 x plus , column 2 y equals 7 , row2 column 1 , negative 2 x plus , column 2 5 y equals negative 1 , end table
-
{
2
x
+
4
y
=
10
3
x
+
5
y
=
14
left brace . table with 2 rows and 1 column , row1 column 1 , 2 x plus 4 y equals 10 , row2 column 1 , 3 x plus 5 y equals 14 , end table
Get Ready! To prepare for Lesson 4-7, do Exercises 99–100.
See Problem 1-3.
Evaluate each expression for the given values of the variables.
-
b
2
−
4
ac
;
a
=
1
,
b
=
6
,
c
=
3
b squared , minus 4 ac semicolon eh equals 1 comma b equals 6 comma c equals 3
-
b
2
−
4
ac
;
a
=
−
5
,
b
=
2
,
c
=
4
b squared , minus 4 ac semicolon eh equals negative 5 comma b equals 2 comma c equals 4