Practice and Problem-Solving Exercises
A Practice
See Problem 1.
Write each expression as a single logarithm.
-
log
7
+
log
2
log 7 plus log 2
-
log
2
9
−
log
2
3
log base 2 , 9 minus , log base 2 , 3
-
5
log
3
+
log
4
5 log 3 plus log 4
-
log
8
−
2
log
6
+
log
3
log 8 minus 2 log 6 plus log 3
-
4
log
m
−
log
n
4 log m minus log n
-
log
5
−
k
log
2
log 5 minus k log 2
-
log
6
5
+
log
6
x
log base 6 , 5 plus , log base 6 , x
-
log
7
x
+
log
7
y
−
log
7
z
log base 7 , x plus , log base 7 , y minus , log base 7 , z
-
log
3
4
+
log
3
y
+
log
3
8
x
log base 3 , 4 plus , log base 3 , y plus , log base 3 . 8 to the x
See Problem 2.
Expand each logarithm.
-
log
x
3
y
5
log , x cubed , y to the fifth
-
log
7
49
x
y
z
log base 7 , 49 x y z
-
log
b
b
x
log base b . b over x
-
log
a
2
log , eh squared
-
log
5
r
s
log base 5 . r over s
-
log
3
(
2
x
)
2
log base 3 , open , 2 to the x , close 2
-
log
3
7
(
2
x
−
3
)
2
log base 3 , 7 open 2 x minus 3 close 2
-
log
a
2
b
3
c
4
log . fraction eh squared , b cubed , over c to the fourth end fraction
-
log
4
5
x
log base 4 , 5 square root of x
-
log
8
8
3
a
5
log base 8 , 8 , square root of 3 , eh to the fifth end root
-
log
5
25
x
log base 5 . 25 over x
-
log
10
m
4
n
−
2
log . 10 m to the fourth . n super negative 2 end super
See Problem 3.
Use the Change of Base Formula to evaluate each expression.
-
log
2
9
log base 2 , 9
-
log
12
20
log base 12 , 20
-
log
7
30
log base 7 , 30
-
log
5
10
log base 5 , 10
-
log
4
7
log base 4 , 7
-
log
3
54
log base 3 , 54
-
log
5
62
log base 5 , 62
-
log
3
33
log base 3 , 33
-
Science The concentration of hydrogen ions in household dish detergent is
10
−
12
.
10 super negative 12 end super . . What is the pH level of household dish detergent?
B Apply
See Problem 4.
Use the properties of logarithms to evaluate each expression.
-
log
2
4
−
log
2
16
log base 2 , 4 minus , log base 2 , 16
-
log
2
96
−
log
2
3
log base 2 , 96 minus , log base 2 , 3
-
log
3
27
−
2
log
3
3
log base 3 , 27 minus 2 , log base 3 , 3
-
log
6
12
+
log
6
3
log base 6 , 12 plus , log base 6 , 3
-
log
4
48
−
1
2
log
4
9
log base 4 , 48 minus , 1 half . log base 4 , 9
-
1
2
log
5
15
−
log
5
75
1 half . log base 5 , 15 minus , log base 5 , square root of 75
-
Think About a Plan The loudness in decibels (dB) of a sound is defined as
10
log
I
I
0
,
10 log . fraction i , over i sub 0 end fraction . comma where I is the intensity of the sound in watts per square meter
(
W/m
2
)
.
I
0
,
open , cap wslashm squared , close . , i sub 0 , comma the intensity of a barely audible sound, is equal to
10
−
12
W/m
2
.
10 super negative 12 end super . cap wslashm squared , . Town regulations require the loudness of construction work not to exceed 100 dB. Suppose a construction team is blasting rock for a roadway. One explosion has an intensity of
1.65
×
10
−
2
1.65 , times , 10 super negative 2 end super
W/m
2
.
cap wslashm squared , . Is this explosion in violation of town regulations?
- Which physical value do you need to calculate to answer the question?
- What values should you use for I and
I
0
?
i sub 0 , question mark
-
Construction The foreman of a construction team puts up a sound barrier that reduces the intensity of the noise by 50%. By how many decibels is the noise reduced? Use the formula
L
=
10
log
I
I
0
l equals 10 log . fraction i , over i sub 0 end fraction to measure loudness. (Hint: Find the difference between the expression for loudness for intensity I and the expression for loudness for intensity 0.
5
I
.
5 to the i , . )
-
Error Analysis Explain why the expansion at the right of
log
4
t
s
log base 4 . square root of t over s end root is incorrect. Then do the expansion correctly.
-
Reasoning Can you expand
log
3
(
2
x
+
1
)
?
log base 3 , open 2 x plus 1 close question mark Explain.
-
Writing Explain why log
(
5
·
2
)
≠
log
5
·
log
2
.
open 5 middle dot 2 close not equal to log 5 middle dot log 2 .