Geometry Review: Special Right Triangles
For Use With Lesson 13-2
In Geometry, you learned about two special right triangles, the 45°
−
45
°
−
90
°
negative 45 degrees negative 90 degrees triangle and the 30°
−
60
°
−
90
°
negative 60 degrees negative 90 degrees triangle. The figures below summarize the relationships among the lengths of the sides of each triangle.
Image Long Description
Example 1
Find the missing side lengths in each 45°
−
45
°
−
90
°
negative 45 degrees negative 90 degrees triangle.
A
|
|
B
|
y
=
2
⋅
5
y
=
5
2
table with 2 rows and 1 column , row1 column 1 , y equals square root of 2 dot 5 , row2 column 1 , y equals 5 square root of 2 , end table
|
hypotenuse
=
2
·
leg
Simplify
.
table with 2 rows and 1 column , row1 column 1 , hypotenuse . equals square root of 2 middle dot leg , row2 column 1 , cap simplify , . , end table
|
5
=
2
⋅
x
x
=
5
2
=
5
2
2
table with 2 rows and 1 column , row1 column 1 , 5 equals square root of 2 dot x , row2 column 1 , x equals , fraction 5 , over square root of 2 end fraction , equals , fraction 5 square root of 2 , over 2 end fraction , end table
|
Example 2
Find the missing side lengths in the
30
°
−
60
°
−
90
°
30 degrees negative 60 degrees negative 90 degrees triangle below.
4
=
3
⋅
x
longer leg
=
3
⋅
shorter leg
x
=
4
3
=
4
3
3
Divide and simplify
.
y
=
2
x
hypotenuse
=
2
⋅
shorter leg
y
=
2
⋅
4
3
3
=
8
3
3
Substitute
4
3
3
for
x
and simplify
.
table with 4 rows and 2 columns , row1 column 1 , 4 equals square root of 3 dot x , column 2 longerleg . equals square root of 3 dot . shorterleg , row2 column 1 , x equals , fraction 4 , over square root of 3 end fraction , equals , fraction 4 square root of 3 , over 3 end fraction , column 2 cap divideandsimplify . . , row3 column 1 , y equals 2 x , column 2 hypotenuse . equals 2 dot . shorterleg , row4 column 1 , y equals 2 dot , fraction 4 square root of 3 , over 3 end fraction , equals , fraction 8 square root of 3 , over 3 end fraction , column 2 cap substitute . fraction 4 square root of 3 , over 3 end fraction . for , x . andsimplify . . , end table
Exercises
Use the given information to find the missing side length(s) in each 45°
−
45
°
−
90
°
negative 45 degrees negative 90 degrees triangle. Rationalize any denominators.
- hypotenuse 1 in.
- leg 2 cm
- hypotenuse
3
square root of 3 ft
- leg
2
5
2 square root of 5 m
Use the given information to find the missing side lengths in each
30
°
−
60
°
−
90
°
30 degrees negative 60 degrees negative 90 degrees triangle. Rationalize any denominators.
- shorter leg 3 in.
- longer leg 1 cm
- hypotenuse 1 ft
- shorter leg
3
square root of 3 cm