C Challenge
-
Writing Explain why 0 cannot be in the domain of an inverse variation.
-
Reasoning Suppose that
(
x
1
,
y
1
)
and
(
x
2
,
y
2
)
open , x sub 1 , comma , y sub 1 , close , and , open , x sub 2 , comma , y sub 2 , close are values from an inverse variation. Show that
x
1
x
2
=
y
2
y
1
.
fraction x sub 1 , over x sub 2 end fraction . equals . fraction y sub 2 , over y sub 1 end fraction . .
-
Open-Ended The height h of a cylinder varies directly with its volume V and inversely with the square of its radius r. Find at least four ways to change the volume and radius of a cylinder so that its height is quadrupled.
Standardized Test Prep
SAT/ACT
- Which equation represents inverse variation between x and y?
-
x
=
y
z
x equals , y over z
-
x
=
−
15
z
y
x equals negative , fraction 15 z , over y end fraction
-
z
=
−
15
y
x
z equals negative , fraction 15 y , over x end fraction
-
x
z
=
5
y
x z equals , 5 to the y
- How can you rewrite the expression
(
8
−
5
i
)
2
open 8 minus , 5 to the i , close squared in the form a + bi?
-
39
+
80
i
39 plus , 80 to the i
-
39
−
80
i
39 minus , 80 to the i
-
89
+
80
i
89 plus , 80 to the i
-
89
−
80
i
89 minus , 80 to the i
- The height of a ball thrown straight up from the ground with a velocity of 96 ft/s is given by the quadratic function
h
(
t
)
=
−
16
t
2
+
96
t
.
h open t close equals negative 16 , t squared , plus , 96 to the t , . What is the maximum height the ball reaches?
- 6 ft
- 128 ft
- 144 ft
- 160 ft
-
Which expression is NOT equivalent to
81
x
4
y
8
6
the sixth , root of 81 , x to the fourth , y to the eighth end root ,
-
(
3
x
y
2
)
2
3
open . 3 x , y squared . close super 2 thirds end super
-
(
3
x
)
2
3
y
4
3
open , 3 x , close super 2 thirds end super . y super 4 thirds end super
-
(
3
x
2
y
2
)
1
3
open . 3 , x squared , y squared . close super 1 third end super
-
9
x
2
y
4
3
cube root of 9 , x squared , y to the fourth end root ,
Short Response
- What is the inverse of
y
=
4
x
2
+
5
?
y equals 4 , x squared , plus 5 question mark Is the inverse a function?
Mixed Review
See Lesson 7-6.
Solve each equation. Check your answers.
-
l
n
4
+
ln
x
=
5
l n 4 plus , ln , x equals 5
-
l
n
x
−
ln
3
=
4
l n x minus , ln , 3 equals 4
- 2ln x + 3ln 4 = 4
See Lesson 6-2.
Multiply and simplify.
-
−
5
6
x
⋅
3
6
x
3
negative 5 , square root of 6 x end root , dot 3 , square root of 6 , x cubed end root
-
3
2
x
2
3
⋅
7
32
x
4
3
3 . cube root of 2 , x squared end root , . dot 7 . cube root of 32 , x to the fourth end root ,
-
5
x
3
⋅
40
x
y
7
square root of 5 , x cubed end root , dot . square root of 40 x , y to the seventh end root
See Lesson 6-1.
Simplify each radical expression. Use absolute value bars where they are needed.
-
x
10
y
100
square root of x to the tenth . y to the 100th end root
-
−
64
a
3
b
6
3
cube root of negative 64 , eh cubed , b to the sixth end root ,
-
64
m
8
n
4
4
the fourth , root of 64 , m to the eighth , n to the fourth end root ,
-
x
n
n
the th , root of x to the n end root ,
Get Ready! To prepare for Lesson 8-2, do Exercises 59-64.
See Lesson 2-7.
Graph each equation. Then describe the transformation of the parent function f(x) = |
x
|.
-
y
=
|
x
|
+
2
y equals vertical line x vertical line plus 2
-
y
=
|
x
+
2
|
y equals vertical line x plus 2 vertical line
-
y
=
|
x
|
−
3
y equals vertical line x vertical line negative 3
-
y
=
|
x
−
3
|
y equals vertical line x minus 3 vertical line
-
y
=
|
x
+
4
|
−
5
y equals vertical line x plus 4 vertical line negative 5
-
y
=
|
x
−
10
|
+
7
y equals vertical line x minus 10 vertical line plus 7