Standardized Test Prep
SAT/ACT
- What is the simplified form of the expression
3
18
x
y
2
fraction 3 , over square root of 18 x , y squared end root end fraction if x and y are positive?
-
2
x
2
x
y
fraction square root of 2 x end root , over 2 x y end fraction
-
2
y
2
x
y
fraction square root of 2 y end root , over 2 x y end fraction
-
54
x
y
2
2
x
y
fraction square root of 54 x , y squared end root , over 2 x y end fraction
-
27
x
y
2
2
x
y
fraction square root of 27 x , y squared end root , over 2 x y end fraction
- What are the solutions, in simplest form, of the quadratic equation
3
x
2
+
6
x
−
5
=
0
?
3 x squared , plus 6 x minus 5 equals 0 question mark
-
−
6
±
96
6
fraction negative 6 plus minus square root of 96 , over 6 end fraction
-
−
6
±
i
24
6
fraction negative 6 plus minus i square root of 24 , over 6 end fraction
-
−
3
±
2
6
3
fraction negative 3 plus minus 2 square root of 6 , over 3 end fraction
-
−
3
±
i
6
3
fraction negative 3 plus minus i square root of 6 , over 3 end fraction
- Which inequality is shown by the graph below?
-
y
≥
2
3
|
x
−
1
|
−
2
y greater than or equal to , 2 thirds absolute value of , x minus 1 , end absolute value , . minus 2
-
y
≥
2
3
|
x
−
2
|
−
1
y greater than or equal to , 2 thirds absolute value of , x minus 2 , end absolute value , . minus 1
-
y
≥
3
2
|
x
−
1
|
−
2
y greater than or equal to , 3 halves absolute value of , x minus 1 , end absolute value , . minus 2
-
y
≥
|
2
3
x
−
1
|
−
2
y greater than or equal to absolute value of . 2 thirds , x minus 1 , end absolute value , . minus 2
-
A triangle has the dimensions shown below.
What is the height of a triangle with equal area but a base of 36?
-
h
3
h over 3
-
2
h
3
fraction 2 h , over 3 end fraction
- 2h
- 3h
Short Response
- Find the axis of symmetry of the graph of the function
y
=
−
2
x
2
−
5
x
+
4
.
y equals negative 2 , x squared , minus 5 x plus 4 . Show your work.
Mixed Review
See Lesson 6-1.
Simplify each radical expression. Use absolute value symbols when needed.
-
121
a
90
square root of 121 , eh to the ninetieth end root
-
81
c
48
d
64
square root of 81 , c to the forty eighth . d to the sixty fourth end root
-
64
a
81
3
cube root of 64 , eh to the eighty first end root ,
-
32
y
25
5
the fifth , root of 32 , y to the twenty fifth end root ,
See Lesson 5-4.
Divide using synthetic division.
-
(
y
3
−
64
)
÷
(
y
+
4
)
open , y cubed , minus 64 close divides open y plus 4 close
-
(
6
a
3
+
a
2
−
a
+
4
)
÷
(
a
+
1
)
open 6 , eh cubed , plus , eh squared , minus eh plus 4 close divides open eh plus 1 close
See Lesson 4-6.
Complete each square.
-
x
2
+
10
x
+
□
x squared , plus 10 x plus white square
-
x
2
−
10
x
+
□
x squared , minus 10 x plus white square
-
x
2
+
11
x
+
□
x squared , plus 11 x plus white square
-
x
2
−
11
x
+
□
x squared , minus 11 x plus white square
Get Ready! To prepare for Lesson 6-3, do Exercises 95-98.
See Lesson 4-8.
Write each quotient as a complex number in the form
a
±
b
i
.
eh plus minus b i .
-
2
3
−
i
fraction 2 , over 3 minus i end fraction
-
5
2
+
3
i
fraction 5 , over 2 plus 3 i end fraction
-
4
4
+
i
fraction 4 , over 4 plus i end fraction
-
−
1
7
−
5
i
fraction negative 1 , over 7 minus 5 i end fraction