Practice and Problem-Solving Exercises
A Practice
See Problem 1.
Simplify each number by using the imaginary number i
.
-
−
4
square root of negative 4 end root
-
−
7
square root of negative 7 end root
-
−
15
square root of negative 15 end root
-
−
81
square root of negative 81 end root
-
−
50
square root of negative 50 end root
See Problem 2.
Plot each complex number and find its absolute value.
- 2 i
- 5 + 12 i
-
2
−
2
i
2 minus 2 i
-
1
−
4
i
1 minus 4 i
-
3
−
6
i
3 minus 6 i
See Problems 3 and 4.
Simplify each expression.
-
(
2
+
4
i
)
+
(
4
−
i
)
open 2 plus 4 i close plus open 4 minus i close
-
(
−
3
−
5
i
)
+
(
4
−
2
i
)
open negative 3 minus 5 i close plus open 4 minus 2 i close
-
(
7
+
9
i
)
+
(
−
5
i
)
open 7 plus 9 i close plus open negative 5 i close
-
(
12
+
5
i
)
−
(
2
−
i
)
open 12 plus 5 i close minus open 2 minus i close
-
(
−
6
−
7
i
)
−
(
1
+
3
i
)
open negative 6 minus 7 i close minus open 1 plus 3 i close
-
(
8
+
i
)
(
2
+
7
i
)
open 8 plus i close open 2 plus 7 i close
-
(
−
6
−
5
i
)
(
1
+
3
i
)
open negative 6 minus 5 i close open 1 plus 3 i close
-
(
−
6
i
)
2
open negative 6 i , close squared
-
(
9
+
4
i
)
2
open 9 plus 4 i , close squared
See Problem 5.
Write each quotient as a complex number.
-
3
−
2
i
5
i
fraction 3 minus 2 i , over 5 i end fraction
-
−
2
i
1
+
i
fraction negative 2 i , over 1 plus i end fraction
-
4
−
3
i
−
1
−
4
i
fraction 4 minus 3 i , over negative 1 minus 4 i end fraction
-
i
+
2
i
−
2
fraction i plus 2 , over i minus 2 end fraction
-
4
2
−
3
i
fraction 4 , over 2 minus 3 i end fraction
-
3
+
2
i
(
1
+
i
)
2
fraction 3 plus 2 i , over open , 1 plus i , close squared end fraction
See Problem 6.
Solve each equation. Check your answer.
-
x
2
+
25
=
0
x squared , plus 25 equals 0
-
2
x
2
+
1
=
0
2 x squared , plus 1 equals 0
-
3
s
2
+
2
=
−
62
3 s squared , plus 2 equals negative 62
-
x
2
=
−
7
x squared , equals negative 7
-
x
2
+
36
=
0
x squared , plus 36 equals 0
-
−
5
x
2
−
3
=
0
negative 5 , x squared , minus 3 equals 0
See Problem 7.
Find all solutions to each quadratic equation.
-
x
2
+
2
x
+
3
=
0
x squared , plus 2 x plus 3 equals 0
-
−
3
x
2
+
x
−
3
=
0
negative 3 , x squared , plus x minus 3 equals 0
-
2
x
2
−
4
x
+
7
=
0
2 x squared , minus 4 x plus 7 equals 0
-
x
2
−
2
x
+
2
=
0
x squared , minus 2 x plus 2 equals 0
-
x
2
+
5
=
4
x
x squared , plus 5 equals 4 x
-
2
x
(
x
−
3
)
=
−
5
2 x open x minus 3 close equals negative 5