Practice and Problem-Solving Exercises
A Practice
See Problems 1, 2, and 3.
Graph each equation. Identify the conic section and describe the graph and its lines of symmetry. Then find the domain and range.
-
3
y
2
−
x
2
=
25
3 y squared , minus . x squared , equals 25
-
2
x
2
+
y
2
=
36
2 x squared , plus , y squared , equals 36
-
x
2
+
y
2
=
16
x squared , plus . y squared , equals 16
-
3
y
2
−
x
2
=
9
3 y squared , minus . x squared , equals 9
-
4
x
2
+
25
y
2
=
100
4 x squared , plus 25 , y squared , equals 100
-
x
2
+
y
2
=
49
x squared , plus . y squared , equals 49
-
x
2
−
y
2
+
1
=
0
x squared , minus , y squared , plus 1 equals 0
-
x
2
−
2
y
2
=
4
x squared , minus , 2 y squared , equals 4
-
6
x
2
+
6
y
2
=
600
6 x squared , plus 6 , y squared , equals 600
-
x
2
+
y
2
−
4
=
0
x squared , plus , y squared , minus 4 equals 0
-
6
x
2
+
24
y
2
−
96
=
0
6 x squared , plus 24 , y squared , minus 96 equals 0
-
4
x
2
+
4
y
2
−
20
=
0
4 x squared , plus 4 , y squared , minus 20 equals 0
-
x
2
+
9
y
2
=
1
x squared , plus 9 , y squared , equals 1
-
4
x
2
−
36
y
2
=
144
4 x squared , minus , 36 y squared , equals 144
-
4
y
2
−
36
x
2
=
1
4 y squared , minus , 36 x squared , equals 1
See Problem 4.
Identify the conic section. Then give the center, intercepts, domain, and range of each graph.
-
-
-
-
-
-
See Problem 5.
Match each equation with a graph in Exercises 22–27.
-
x
2
−
y
2
=
9
x squared , minus . y squared , equals 9
-
4
x
2
+
9
y
2
=
36
4 x squared , plus 9 , y squared , equals 36
-
y
2
−
x
2
=
4
y squared , minus , x squared , equals 4
-
x
2
+
4
y
2
=
64
x squared , plus 4 , y squared , equals 64
-
25
x
2
+
9
y
2
=
225
25 x squared , plus 9 , y squared , equals 225
-
y
2
−
x
2
=
9
y squared , minus . x squared , equals 9
B Apply
Graph each equation. Describe the graph and its lines of symmetry. Then find the domain and range.
-
9
x
2
−
y
2
=
144
9 x squared , minus , y squared , equals 144
-
11
x
2
+
11
y
2
=
44
11 x squared , plus 11 , y squared , equals 44
-
−
8
x
2
+
32
y
2
−
128
=
0
negative 8 x squared . plus , 32 y squared , minus 128 equals 0
-
25
x
2
+
16
y
2
−
320
=
0
25 x squared , plus 16 , y squared , minus 320 equals 0