10-1 Exploring Conic Sections
Quick Review
A conic section is formed by the intersection of a plane and a double cone. Circles, ellipses, parabolas, and hyperbolas are all conic sections.
Example
Graph the equation
x
2
+
y
2
=
9
.
x squared , plus . y squared , equals 9 . Identify the conic section, the domain and range.
Plot points that satisfy the equation. Connect them with a smooth curve.
The graph is a circle with center (0, 0) and radius 3.
The domain is
−
3
≤
x
≤
3
.
negative 3 less than or equal to x less than or equal to 3 .
The range is
−
3
≤
y
≤
3
.
negative 3 less than or equal to y less than or equal to 3 .
Exercises
Graph each equation. Identify the conic section, any lines of symmetry, and the domain and range.
-
x
2
49
+
y
2
121
=
1
fraction x squared , over 49 end fraction , plus . fraction y squared , over 121 end fraction . equals 1
-
x
2
+
y
2
=
4
x squared , plus . y squared , equals 4
-
x
2
25
−
y
2
4
=
1
fraction x squared , over 25 end fraction , minus , fraction y squared , over 4 end fraction , equals 1
-
x
=
2
y
2
+
5
x equals , 2 y squared , plus 5
Identify the center and domain and range of each graph.
-
Image Long Description
-
10-2 Parabolas
Quick Review
In a plane, a parabola is the set of all points that are the same distance, c, from a fixed point, the focus and a fixed line, the directrix.
For
y
=
a
x
2
,
y equals , eh x squared , comma if
a
>
0
,
eh greater than 0 comma the parabola opens up, and has focus (0, c) and directrix
y
=
−
c
;
y equals negative c semicolon if
a
<
0
,
eh less than 0 comma the parabola opens down, and has focus
(
0
,
−
c
)
open 0 comma negative c close and directrix
y
=
c
.
y equals c .
For
x
=
a
y
2
,
x equals , eh y squared , comma if
a
>
0
,
eh greater than 0 comma the parabola opens right, and has focus (c, 0) and directrix
x
=
−
c
;
x equals negative c semicolon if
a
<
0
,
eh less than 0 comma the parabola opens left, and has focus
(
−
c
,
0
)
open negative c comma 0 close and directrix
x
=
c
.
x equals c . In all cases,
a
=
1
4
c
.
eh equals , fraction 1 , over 4 c end fraction , .
Example
Write an equation of a parabola that opens up, with vertex at the origin and focus 1 unit from the vertex.
Since the parabola opens up, use
y
=
a
x
2
.
y equals , eh x squared , . Since the focus is 1 unit from the vertex,
c
=
1
.
c equals 1 .
a
=
1
4
c
=
1
4
(
1
)
=
1
4
eh equals , fraction 1 , over 4 c end fraction , equals . fraction 1 , over 4 , open 1 close end fraction . equals , 1 fourth
An equation for the parabola is
y
=
1
4
x
2
.
y equals , 1 fourth , x squared , .
Exercises
Write an equation of a parabola with vertex at the origin and the given focus.
- (5, 0)
-
(
0
,
−
5
)
open 0 comma negative 5 close
- (0, 6)
Write an equation of a parabola that opens up, with vertex at the origin and a focus as described.
- focus is 2.5 units from the vertex
- focus is
1
12
1 twelfth of a unit from the vertex
Write an equation of a parabola with the given focus and directrix.
- focus: (0, 3); directrix:
y
=
−
1
y equals negative 1
- focus:
(
−
2
,
0
)
;
open negative 2 comma 0 close semicolon directrix:
x
=
4
x equals 4
Find the focus and the directrix of the graph of each equation. Sketch the graph.
-
y
=
5
x
2
y equals , 5 x squared
-
x
=
2
y
2
x equals , 2 y squared
-
x
=
−
1
8
y
2
x equals negative , 1 eighth , y squared