13-7 Translating Sine and Cosine Functions
Quick Review
Each horizontal translation of certain periodic functions is a phase shift. When
g
(
x
)
=
f
(
x
−
h
)
+
k
,
g open x close equals f open x minus h close plus k comma the value of h is the amount of the horizontal shift and the value of k is the amount of the vertical shift.
Example
What is an equation for the translation of
y
=
sin
x
,
2
y equals sine x comma 2 units to the right and 1 unit up?
2 units to the right means
h
=
2
h equals 2 and 1 unit up means
k
=
1
.
k equals 1 .
An equation is
y
=
sin
(
x
−
2
)
+
1
.
y equals sine open x minus 2 close plus 1 .
Exercises
Graph each function in the inteval from 0 to 2π.
-
y
=
cos
(
x
+
π
2
)
y equals cosine . open . x plus , pi over 2 . close
-
y
=
2
sin
x
−
4
y equals 2 sine x minus 4
-
y
=
sin
(
x
−
π
)
+
3
y equals sine open x minus pi close plus 3
-
y
=
cos
(
x
+
π
)
−
1
y equals cosine open x plus pi close minus 1
Write an equation for each translation.
-
y
=
sin
x
,
π
4
y equals sine x comma , pi over 4 units to the right
-
y
=
cos
x
,
y equals cosine x comma 2 units down
13-8 Reciprocal Trigonometric Functions
Quick Review
The cosecant (csc), secant (sec), and cotangent (cot) functions are defined as reciprocals for all real numbers θ (except those that make a denominator zero).
csc
θ
=
1
sin
θ
sec
θ
=
1
cos
θ
cot
θ
=
1
tan
θ
co-secant theta equals . fraction 1 , over sine theta end fraction secant theta equals . fraction 1 , over cosine theta end fraction co-tangent theta equals . fraction 1 , over tangent theta end fraction
Example
Suppose
sin
θ
=
−
3
5
.
sine theta equals negative , 3 fifths , . Find csc θ.
csc
θ
=
1
sin
θ
=
1
−
3
5
=
−
5
3
co-secant theta equals . fraction 1 , over sine theta end fraction . equals . fraction 1 , over fraction negative 3 , over 5 end fraction end fraction . equals negative , 5 thirds
Exercises
Evaluate each expression. Write your answer in exact form.
-
sec
(
−
45
°
)
secant open negative 45 degrees close
-
cot
120
°
co-tangent , 120 degrees
-
csc
150
°
co-secant , 150 degrees
-
cot
(
−
150
°
)
co-tangent open negative 150 degrees close
Graph each function in the interval from 0 to 4π.
-
y
=
2
csc
θ
y equals 2 csc theta
-
y
=
sec
θ
−
1
y equals secant theta negative 1
-
y
=
cot
1
4
θ
y equals co-tangent , 1 fourth , theta
-
y
=
csc
1
2
θ
+
2
y equals co-secant , 1 half , theta plus 2