C Challenge
-
Reasoning Find a sequence of basic transformations by which the polynomial function
y
=
2
x
3
−
6
x
2
+
6
x
+
5
y equals 2 , x cubed , minus , 6 x squared , plus 6 x plus 5 can be derived from the cubic function
y
=
x
3
.
y equals , x cubed , .
-
Physics For a constant resistance R (in ohms), the power P (in watts) dissipated across two terminals of a battery varies directly as the square of the current I (in amps). If a battery connected in a circuit dissipates 24 watts of power for 2 amps of current flow, how much power would be dissipated when the current flow is 5 amps?
-
Writing Give an argument that shows that every polynomial family of degree
n
>
2
n greater than 2 contains polynomials that cannot be generated from the basic function
y
=
x
n
y equals , x to the n by using stretches, compressions, reflections, and translations.
Standardized Test Prep
Use the graph to answer questions 47–49.
SAT/ACT
-
Which equation does the graph represent?
-
y
=
(
x
+
2
)
2
−
1
y equals open x plus 2 , close squared , minus 1
-
y
=
(
x
−
2
)
2
−
1
y equals . open x minus 2 close squared . minus 1
-
y
=
(
x
−
2
)
2
−
1
y equals . open x minus 2 close squared . minus 1
-
y
=
(
x
−
2
)
4
−
1
y equals . open x minus 2 close to the fourth . minus 1
-
If
y
=
f
(
x
)
y equals f open x close is an equation for the graph, what are factors of
f
(
x
)
?
f open x close question mark
-
(
x
−
1
)
and
(
x
+
3
)
open x minus 1 close , and , open x plus 3 close
-
(
x
−
1
)
and
(
x
−
3
)
open x minus 1 close , and , open x minus 3 close
-
(
x
+
1
)
and
(
x
−
3
)
open x plus 1 close , and , open x minus 3 close
-
(
x
+
1
)
and
(
x
+
3
)
open x plus 1 close , and , open x plus 3 close
Short Response
- If
y
=
a
x
2
+
b
x
+
c
y equals eh , x squared , plus b x plus c is an equation for the graph, what type of number is its discriminant?
Mixed Review
See Lesson 5-8.
Find a polynomial function whose graph passes through the given points.
-
(
−
1
,
4
)
,
(
0
,
−
2
)
,
(
1
,
−
2
)
,
(
2
,
−
8
)
open negative 1 comma 4 close comma open 0 comma negative 2 close comma open 1 comma negative 2 close comma open 2 comma negative 8 close
-
(
−
2
,
−
17
)
,
(
0
,
−
3
)
,
(
1
,
−
5
)
,
(
3
,
63
)
open negative 2 comma negative 17 close comma open 0 comma negative 3 close comma open 1 comma negative 5 close comma open 3 comma 63 close
See Lesson 2-4.
Write an equation of each line.
-
slope
=
−
4
5
;
slope , equals negative , 4 fifths . semicolon through
(
−
1
,
4
)
open negative 1 comma 4 close
-
slope
=
−
3
;
slope , equals negative 3 semicolon through
(
2
,
−
1
)
open 2 comma negative 1 close
See Lesson 2-1.
Determine whether each relation is a function.
-
{
(
0
,
−
1
)
,
(
−
1
,
3
)
,
(
2
,
3
)
,
(
−
3
,
3
)
}
the set open 0 comma negative 1 close comma open negative 1 comma 3 close comma open 2 comma 3 close comma open negative 3 comma 3 close end set
-
{
(
−
4
,
0
)
,
(
−
7
,
0
)
,
(
−
4
,
1
)
,
(
−
7
,
1
)
}
the set open negative 4 comma 0 close comma open negative 7 comma 0 close comma open negative 4 comma 1 close comma open negative 7 comma 1 close end set
Get Ready! To prepare for Lesson 6-1, do Exercises 56–58.
See Lesson 5-2.
Factor each expression.
-
x
10
+
x
2
x to the tenth , plus , x squared
-
x
4
−
y
4
x to the fourth , minus , y to the fourth
-
169
x
6
y
12
−
13
x
3
y
6
169 , x to the sixth , y to the twelfth , minus , 13 x cubed . y to the sixth