-
Physics When a ray of light passes from one medium into a second, the angle of incidence
θ
1
theta sub 1 and the angle of refraction
θ
2
theta sub 2 are related by Snell's law:
n
1
sin
θ
1
=
n
2
sin
θ
2
,
n sub 1 sine , theta sub 1 , equals , n sub 2 sine , theta sub 2 , comma where
n
1
n sub 1 is the index of refraction of the first medium and
n
2
n sub 2 is the index of refraction of the second medium. How are
θ
1
theta sub 1 and
θ
2
theta sub 2 related if
n
2
>
n
1
?
n sub 2 , greater than , n sub 1 , question mark If
n
2
<
n
1
?
n sub 2 , less than , n sub 1 , question mark If
n
2
=
n
1
?
n sub 2 , equals , n sub 1 , question mark
Standardized Test Prep
SAT/ACT
- Which expression is equivalent to 2
cot
θ
?
co-tangent theta question mark
-
1
2
tan
θ
fraction 1 , over 2 tangent theta end fraction
-
2
cot
θ
fraction 2 , over co-tangent theta end fraction
-
2
cos
θ
sin
θ
fraction 2 cosine theta , over sine theta end fraction
-
sin
θ
1
2
cos
θ
fraction sine theta , over 1 half cosine theta end fraction
- Which equation is NOT an identity?
-
cos
2
θ
=
1
−
sin
2
θ
cosine squared , theta equals 1 minus , sine squared , theta
-
cot
2
θ
=
csc
2
θ
−
1
co-tangent squared , theta equals , co-secant squared , theta negative 1
-
sin
2
θ
=
cos
2
θ
−
1
sine squared , theta equals , cosine squared , theta negative 1
-
tan
2
θ
=
sec
2
θ
−
1
tangent squared , theta equals , secant squared , theta negative 1
- Which expressions are equivalent?
-
(
sin
θ
)
(
csc
θ
−
sin
θ
)
open sine theta close open co-secant theta negative sine theta close
-
sin
2
θ
−
1
sine squared , theta negative 1
-
cos
2
θ
cosine squared , theta
- I and II only
- II and III only
- I and III only
- I, II, and III
- How can you express
csc
2
θ
−
2
cot
2
θ
in terms of
sin
θ
and
cos
θ
?
co-secant squared , theta negative 2 , co-tangent squared , theta . intermsof sine theta , and cosine theta question mark
-
1
−
2
cos
2
θ
sin
2
θ
fraction 1 minus 2 , cosine squared , theta , over sine squared , theta end fraction
-
1
−
2
sin
2
θ
sin
2
θ
fraction 1 minus 2 , sine squared , theta , over sine squared , theta end fraction
-
sin
2
θ
−
2
cos
2
θ
sine squared , theta negative 2 , cosine squared , theta
-
1
sin
2
θ
−
1
tan
2
θ
fraction 1 , over sine squared , theta end fraction . minus . fraction 1 , over tangent squared , theta end fraction
- Which expression is equivalent to
tan
θ
cos
θ
−
sec
θ
?
fraction tangent theta , over cosine theta minus secant theta end fraction . question mark
-
csc
θ
co-secant theta
-
sec
θ
secant theta
-
−
csc
θ
negative co-secant theta
-
tan
2
θ
tangent squared , theta
Short Response
- Show that
(
sec
θ
+
1
)
(
sec
θ
−
1
)
=
tan
2
θ
open secant theta plus 1 close open secant theta negative 1 close equals , tangent squared , theta is an identity.
Mixed Review
Graph each function in the interval from 0 to 2π. See Lesson 13-8.
-
y
=
csc
(
−
θ
)
y equals co-secant open negative theta close
-
y
=
−
sec
0.5
θ
y equals negative secant , 0.5 theta
-
y
=
−
sec
(
0.5
θ
+
2
)
y equals negative secant open 0.5 theta plus 2 close
-
y
=
π
sec
θ
y equals pi secant theta
Find the measure of an angle between
0
°
and
360
°
0 degrees . ehnd , 360 degrees that is coterminal with the given angle. See Lesson 13-2.
-
395
°
395 degrees
-
405
°
405 degrees
-
−
225
°
negative 225 degrees
-
−
149
°
negative 149 degrees
Get Ready! To prepare for Lesson 14-2, do Exercises 78–80.
For each function f, find
f
−
1
.
f super negative 1 end super , . See Lesson 6-7.
-
f
(
x
)
=
x
+
1
f open x close equals x plus 1
-
f
(
x
)
=
2
x
−
3
f open x close equals 2 x minus 3
-
f
(
x
)
=
x
2
+
4
f open x close equals , x squared , plus 4