13-5 The Cosine Function
Quick Review
The cosine function
y
=
cos
θ
y equals cosine theta matches the measure θ of an angle in standard position with the x-coordinate of a point on the unit circle. This point is where the terminal side of the angle intersects the unit circle.
For the cosine function
y
=
a
cos
b
θ
,
y equals eh cosine b theta comma the amplitude equals | a |, there are b cycles from 0 to 2π, and the period is
2
π
b
.
fraction 2 pi , over b end fraction , .
Example
Find all solutions to
5
cos
θ
=
−
4
5 cosine theta equals negative 4 in the interval from 0 to 2π. Round each answer to the nearest hundredth.
On a graphing calculator graph the equations
y
=
−
4
y equals negative 4 and
y
=
5
cos
θ
.
y equals 5 cosine theta .
Use the Intersect feature to find the points at which the two graphs intersect. The graph shows two solutions in the interval. They are
θ
≈
2
.
50
and
3
.
79
theta almost equal to 2 . 50 , and , 3 . 79
Exercises
Sketch the graph of each function in the interval from 0 to 2π.
-
y
=
2
cos
(
π
2
θ
)
y equals 2 cosine . open , pi over 2 , theta , close
-
y
=
−
cos
2
θ
y equals negative cosine 2 theta
- Write an equation of a cosine function with
a
>
0
,
eh greater than 0 comma amplitude 3, and period π.
Solve each equation in the interval from 0 to 2π. Round your answer to the nearest hundredth.
-
3
cos
4
θ
=
−
2
3 cosine 4 theta equals negative 2
-
cos
(
π
θ
)
=
−
0.6
cosine open pi theta close equals negative 0.6
13-6 The Tangent Function
Quick Review
The tangent of an angle θ in standard position is the y-coordinate of the point where the terminal side of the angle intersects the tangent line
x
=
1
.
x equals 1 . A tangent function in the form
y
=
a
tan
b
θ
y equals eh tangent b theta has a period of
π
b
.
pi over b , .
Example
What is the period of
y
=
tan
π
4
θ
?
y equals tangent , pi over 4 , theta . question mark Tell where two asymptotes occur.
period
=
π
b
=
π
π
4
=
4
period , equals , pi over b , equals , fraction pi , over fraction pi , over 4 end fraction end fraction , equals 4
One cycle occurs in the interval from
−
2
negative 2 to 2, so there are asymptotes at
θ
=
−
2
and
θ
=
2
.
theta equals negative 2 , and , theta equals 2 .
Exercises
Graph each function in the interval from 0 to 2π. Then evaluate the function at
t
=
π
4
t equals , pi over 4 and
t
=
π
2
.
t equals , pi over 2 . . If the tangent is undefined at that point, write undefined.
-
y
=
tan
1
2
t
y equals tangent , 1 half , t
-
y
=
tan
3
t
y equals tangent 3 t
-
y
=
2
tan
t
y equals 2 tangent t
-
y
=
4
tan
2
t
y equals 4 tangent 2 t