C Challenge
- Use the Fundamental Theorem of Algebra and the Conjugate Root Theorem to show that any odd degree polynomial equation with real coefficients has at least one real root.
-
Reasoning What is the maximum number of points of intersection between the graphs of a quartic and a quintic polynomial function?
-
Reasoning What is the least possible degree of a polynomial with rational coefficients, leading coefficient 1, constant term 5, and zeros at
2
square root of 2 and
3
?
square root of 3 question mark Show that such a polynomial has a rational zero and indicate this zero.
Standardized Test Prep
SAT/ACT
-
How many roots does
f
(
x
)
=
x
4
+
5
x
3
+
3
x
2
+
2
x
+
6
f open x close equals , x to the fourth , plus 5 , x cubed , plus , 3 x squared , plus 2 x plus 6 have?
- 5
- 4
- 3
- 2
- Which translation takes
y
=
|
x
+
2
|
−
1
to
y
=
|
x
|
+
2
?
y equals vertical line x plus 2 vertical line negative 1 , to , y equals vertical line x vertical line plus 2 question mark
- 2 units right, 3 units down
- 2 units right, 3 units up
- 2 units left, 3 units up
- 2 units left, 3 units down
- What is the factored form of the expression
x
4
−
3
x
3
+
2
x
2
?
x to the fourth , minus , 3 x cubed , plus 2 , x squared , question mark
-
x
2
(
x
−
1
)
(
x
+
2
)
x squared , open x minus 1 close open x plus 2 close
-
x
2
(
x
+
1
)
(
x
+
2
)
x squared , open x plus 1 close open x plus 2 close
-
x
2
(
x
+
1
)
(
x
−
2
)
x squared , open x plus 1 close open x minus 2 close
-
x
2
(
x
−
1
)
(
x
−
2
)
x squared , open x minus 1 close open x minus 2 close
Short Response
- How would you test whether
(
2
,
−
2
)
open 2 comma negative 2 close is a solution of the system?
{
y
<
−
2
x
+
3
y
≥
x
−
4
left brace . table with 2 rows and 1 column , row1 column 1 , y less than negative 2 x plus 3 , row2 column 1 , y greater than or equal to x minus 4 , end table
Mixed Review
See Lesson 5-5.
-
Find a fourth-degree polynomial equation with real coefficients that has
2
i
2 i and
−
3
+
i
negative 3 plus i as roots.
See Lesson 4-7.
Solve each equation using the Quadratic Formula.
-
x
2
−
6
x
+
1
=
0
x squared , minus 6 x plus 1 equals 0
-
2
x
2
+
5
x
=
−
9
2 x squared , plus 5 x equals negative 9
-
2
(
x
2
+
2
)
=
3
x
2 open , x squared , plus 2 close equals 3 x
See Lesson 4-3.
Determine whether a quadratic model exists for each set of values. If so, write the model.
-
f
(
−
1
)
=
0
,
f
(
2
)
=
3
,
f
(
1
)
=
4
f open negative 1 close equals 0 comma f open 2 close equals 3 comma f open 1 close equals 4
-
f
(
−
4
)
=
11
,
f
(
−
5
)
=
5
,
f
(
−
6
)
=
3
f open negative 4 close equals 11 comma f open negative 5 close equals 5 comma f open negative 6 close equals 3
Get Ready! To prepare for Lesson 5-7, do Exercises 60–65.
See Lesson 4-2.
Write each polynomial in standard form.
-
(
x
+
1
)
3
open x plus 1 close cubed
-
(
x
−
3
)
3
open x minus 3 close cubed
-
(
x
−
2
)
4
open x minus 2 close to the fourth
-
(
x
−
1
)
2
open x minus 1 close squared
-
(
x
+
5
)
3
open x plus 5 close cubed
-
(
4
−
x
)
3
open 4 minus x close cubed