C Challenge
- The function
S
(
n
)
=
10
(
1
−
0.8
n
)
0.2
s , open n close , equals . fraction 10 . open . 1 minus , 0.8 to the n . close , over 0.2 end fraction represents the sum of the first n terms of an infinite geometric series.
- What is the domain of the function?
- Find
S
(
n
)
s open n close for
n
=
1
,
2
,
3
,
…
,
10
.
n equals 1 , comma 2 comma 3 comma dot dot dot comma 10 . Sketch the graph of the function.
- Find the sum S of the infinite geometric series.
- Use the formula for the sum of an infinite geometric series to show that
0.
9
¯
=
1
.
0. , 9 bar , equals 1 . (Hint:
0.
9
¯
=
9
10
+
9
100
+
9
1000
=
…
0. , 9 bar , equals , 9 tenths , plus , 9 100ths , plus , 9 over 1000 , equals dot dot dot )
Standardized Test Prep
GRIDDED RESPONSE
SAT/ACT
- What is the value of
∑
n
=
1
5
(
2
n
−
3
)
?
sum , from , n equals 1 , to , 5 , of . open , 2 n minus 3 , close . question mark
- Evaluate the infinite geometric series
2
5
+
4
25
+
8
125
+
…
.
2 fifths , plus , 4 twenty fifths , plus , 8 over 125 , plus dot dot dot . Enter your answer as a fraction.
- Use
log
5
2
≈
0.43
log base 5 , 2 almost equal to , 0.43 and
log
5
7
≈
1.21
log base 5 , 7 almost equal to , 1.21 and the properties of logarithms to approximate
log
5
14
log base 5 , square root of 14 without using a calculator.
- Use a calculator to solve the equation
7
2
x
=
75
.
7 super 2 x end super , equals 75 . Round the answer to the nearest hundredth.
- Use the Change of Base Formula and a calculator to solve
log
9
x
=
log
6
15
.
log base 9 , x equals , log base 6 , 15 . Round the answer to the nearest tenth.
Mixed Review
See Lesson 9-4.
Evaluate each series to the given term.
-
12
.
5
+
15
+
17
.
5
+
20
+
22
.
5
+
…
;
12 . 5 plus 15 plus 17 . 5 plus 20 plus 22 . 5 plus dot dot dot semicolon 7th term
-
−
100
−
95
−
90
−
85
−
…
;
negative 100 minus . 95 minus 90 minus 85 . minus dot dot dot semicolon 11th term
See Lesson 8-5.
Add or subtract. Simplify where possible.
-
7
2
c
−
2
c
2
fraction 7 , over 2 c end fraction , minus , fraction 2 , over c squared end fraction
-
5
y
+
3
+
15
y
−
3
fraction 5 , over y plus 3 end fraction . plus . fraction 15 , over y minus 3 end fraction
-
4
x
2
−
36
+
x
x
−
6
fraction 4 , over x squared , minus 36 end fraction . plus . fraction x , over x minus 6 end fraction
See Lesson 7-4.
Use the properties of logarithms to evaluate each expression.
-
log
2
1
8
+
log
2
8
log base 2 . 1 eighth , plus , log base 2 , 8
-
log
15
25
+
log
15
9
log base 15 , 25 plus , log base 15 , 9
-
3
log
9
3
−
1
4
log
9
81
3 , log base 9 , 3 minus , 1 fourth . log base 9 , 81
Get Ready! To prepare for Lesson 10-1, do Exercises 67–69.
See Lesson 4-2.
Graph each function.
-
y
=
x
2
−
4
y equals . x squared , minus 4
-
y
=
x
2
−
6
x
−
9
y equals . x squared , minus , 6 x minus 9
-
y
=
−
4
x
2
+
1
y equals minus . 4 x squared , plus 1