C Challenge
-
Sailing Buoys are located in the sea at points A, B, and C.
∠
angle
ACB is a right angle.
A
C
=
3.0
eh c equals 3.0 mi,
B
C
=
4.0
b c equals 4.0 mi, and
A
B
=
5.0
eh b equals 5.0 mi. A ship is located at point D on
A
B
¯
eh b bar so that
m
∠
m angle
ACD
=
30
°
.
equals , 30 degrees . How far is the ship from the buoy at point C? Round your answer to the nearest tenth of a mile.
-
Writing Suppose you know the measures of all three angles of a triangle. Can you use the Law of Sines to find the lengths of the sides? Explain.
Standardized Test Prep
SAT/ACT
- In
Δ
GDL
,
m
∠
D
=
57
°
,
D
L
=
10.1
cap delta , and
G
L
=
9.4
g l equals 9.4 . What is the best estimate for
m
∠
G
m angle g ?
-
64
°
64 degrees
-
51
°
51 degrees
-
39
°
39 degrees
-
26
°
26 degrees
- For which set of given information can you compute the area of
Δ
ABC
cap delta ?
-
m
∠
C
=
58
°
,
c
=
23
m angle c equals , 58 degrees comma , c equals 23
-
m
∠
B
=
26
°
,
a
=
43
m angle b equals , 26 degrees comma , eh equals 43
-
m
∠
C
=
58
°
,
a
=
43
,
c
=
23
m angle c equals , 58 degrees comma , eh equals 43 comma c equals 23
-
m
∠
C
=
26
°
,
a
=
43
,
b
=
23
m angle c equals , 26 degrees comma , eh equals 43 comma b equals 23
- Two points in front of a tall building are 250 m apart. The angles of elevation of the top of the building from the two points are
37
°
37 degrees and
13
°
.
13 degrees . What is the best estimate for the height of the building?
- 150 m
- 138 m
- 83 m
- 56 m
Short Response
- Two sides of a scalene triangle are 9 m and 14 m. The area of the triangle is
31.5
m
2
.
31.5 , m squared , . Find the measure of one of the angles of the triangle to the nearest tenth of a degree. Show your work.
Mixed Review
Sketch one cycle of the graph of each sine function. See Lesson 13-4.
-
y
=
4
sin
θ
y equals 4 sine theta
-
y
=
4
sin
π
θ
y equals 4 sine pi theta
-
y
=
sin
4
θ
y equals sine 4 theta
Let
u
=
(
−
2
,
3
)
,
v
=
(
1
,
4
)
,
and
w
=
(
4
,
−
1
)
.
u equals open negative 2 comma 3 close comma v equals open 1 comma 4 close comma , and , w equals open 4 comma negative 1 close .
Find the component form of each vector. See Lesson 12-6.
-
u
+
v
u plus v
-
v
+
w
v plus w
-
u
−
v
u minus , v
-
u
−
w
u minus , w
Get Ready! To prepare for Lesson 14-5, do Exercises 47–50.
Find each angle measure to the nearest tenth of a degree. See Lesson 14-3.
-
cos
−
1
3
5
cosine super negative 1 end super . 3 fifths
-
tan
−
1
0.4569
tangent super negative 1 end super . 0.4569
-
sin
−
1
5
8
sine super negative 1 end super . 5 eighths
-
tan
−
1
2
tangent super negative 1 end super . square root of 2