12-5 Geometric Transformations
Quick Review
A change made to a figure is a transformation. The original figure is the preimage, and the transformed figure is the image. A translation slides a figure without changing its size or shape. A dilation changes the size of a figure. You can use matrix addition to translate a figure and scalar multiplication to dilate a figure.
You can use multiplication by the appropriate matrix to perform transformations that are specific reflections or rotations. For example, to reflect a figure across the y-axis, multiply by
[
−
1
0
0
1
]
.
. matrix with 2 rows and 2 columns , row1 column 1 , negative 1 , column 2 0 , row2 column 1 , 0 , column 2 1 , end matrix . .
Example
A triangle has vertices A(3, 2), B
(
1
,
−
2
)
,
open 1 comma negative 2 close comma and C(1, 2). What are the coordinates after a 90° rotation?
[
0
−
1
1
0
]
[
3
1
1
2
−
2
2
]
=
[
−
2
2
−
2
3
1
1
]
. matrix with 2 rows and 2 columns , row1 column 1 , 0 , column 2 negative 1 , row2 column 1 , 1 , column 2 0 , end matrix . matrix with 2 rows and 3 columns , row1 column 1 , 3 , column 2 1 , column 3 1 , row2 column 1 , 2 , column 2 negative 2 , column 3 2 , end matrix . equals . matrix with 2 rows and 3 columns , row1 column 1 , negative 2 , column 2 2 , column 3 negative 2 , row2 column 1 , 3 , column 2 1 , column 3 1 , end matrix
The coordinates are
(
−
2
,
3
)
,
(
open negative 2 comma 3 close comma open 2, 1), and
(
−
2
,
1
)
.
open negative 2 comma 1 close .
Exercises
In matrix form, write the coordinates of each image of the triangle with vertices A(3, 1), B
(
−
2
,
0
)
,
open negative 2 comma 0 close comma and C(1, 5).
- a translation 3 units left and 4 units up
- a reflection across the y-axis
- a reflection across the line
y
=
x
y equals x
- a dilation half the original size
- a dilation twice the original size
- a rotation of
270
°
270 degrees
12-6 Vectors
Quick Review
A vector has both magnitude and direction. It is a directed line segment that you can describe using a pair of initial and terminal points. If a vector were in standard position with the initial point at (0, 0), the component form would be (a, b) and the magnitude
|
v
|
=
a
2
+
b
2
absolute value of v , end absolute value , , equals . square root of eh squared , plus , b squared end root would give you the length.
Given two vectors v = 〈
v
1
,
v
2
v sub 1 , comma , v sub 2 〉 and w = 〈
w
1
,
w
2
w sub 1 , comma , w sub 2 〉, the dot product
v
·
w
v middle dot w is
v
1
w
1
+
v
2
w
2
.
v sub 1 , w sub 1 , plus , v sub 2 , w sub 2 , . If the dot product equals 0, then v and w are normal, or perpendicular, to each other.
Example
Are the vectors
〈
−
1
,
2
〉
left pointing angle bracket negative 1 comma 2 right pointing angle bracket and 〈4, 2〉 normal?
〈
−
1
,
2
〉
·
〈
4
,
2
〉
=
(
−
1
)
(
4
)
+
(
2
)
(
2
)
=
−
4
+
4
=
0
table with 2 rows and 2 columns , row1 column 1 , left pointing angle bracket negative 1 comma 2 right pointing angle bracket middle dot left pointing angle bracket 4 comma 2 right pointing angle bracket , column 2 equals open negative 1 close open 4 close plus open 2 close open 2 close , row2 column 1 , , column 2 equals negative 4 plus 4 equals 0 , end table
The vectors are normal.
Exercises
Let u = 〈
−
3
,
negative 3 comma 4〉, v = 〈2, 4〉, and w = 〈4,
−
1
negative 1 〉. Write each resulting vector in component form and find the magnitude.
-
u
+
v
u plus v
-
w
−
u
w minus u
- 3u
-
−
2
w
+
3
v
negative 2 w plus 3 v
-
1
2
v
+
3
u
1 half , v plus 3 u
-
−
w
+
3
v
+
2
u
negative w plus 3 v plus 2 u
Find the dot product of each pair of vectors and determine whether they are normal.
- 〈4,
−
3
negative 3 〉 and 〈
−
3
,
−
4
negative 3 comma negative 4 〉
-
[
1
7
]
, matrix with 2 rows and 1 column , row1 column 1 , 1 , row2 column 1 , 7 , end matrix and
[
14
−
2
]
. matrix with 2 rows and 1 column , row1 column 1 , 14 , row2 column 1 , negative 2 , end matrix