B Apply
-
- Name the complex number represented by each point on the graph below.
- Find the additive inverse of each number.
- Find the complex conjugate of each number.
- Find the absolute value of each number.
Image Long Description
-
Think About a Plan In the complex number plane, what geometric figure describes the complex numbers with absolute value 10?
- What does the absolute value of a complex number represent?
- How can you use the complex number plane to solve this problem?
- Solve
(
x
+
3
i
)
(
x
−
3
i
)
=
34
.
open x plus 3 i close open x minus 3 i close equals 34 .
Simplify each expression.
-
(
8
i
)
(
4
i
)
(
−
9
i
)
open 8 i close open 4 i close open negative 9 i close
-
(
2
+
−
1
)
+
(
−
3
+
−
16
)
open . 2 plus , square root of negative 1 end root . close . plus . open . negative 3 plus , square root of negative 16 end root . close
-
(
4
+
−
9
)
+
(
6
−
−
49
)
open . 4 plus , square root of negative 9 end root . close . plus . open . 6 minus , square root of negative 49 end root . close
-
(
10
+
−
9
)
−
(
2
+
−
25
)
open . 10 plus , square root of negative 9 end root . close . minus . open . 2 plus , square root of negative 25 end root . close
-
(
8
−
−
1
)
−
(
−
3
+
−
16
)
open . 8 minus , square root of negative 1 end root . close . minus . open . negative 3 plus , square root of negative 16 end root . close
-
2
i
(
5
−
3
i
)
2 i open 5 minus 3 i close
-
−
5
(
1
+
2
i
)
+
3
i
(
3
−
4
i
)
negative 5 open 1 plus 2 i close plus 3 i open 3 minus 4 i close
-
(
3
+
−
4
)
(
4
+
−
1
)
open . 3 plus , square root of negative 4 end root . close . open . 4 plus , square root of negative 1 end root . close
-
Open-Ended In the equation
x
2
−
6
x
+
c
=
0
,
x squared , minus 6 x plus c equals 0 comma find values of c that will give:
- two real solutions
- two imaginary solutions
- one real solution
- A student wrote the numbers 1, 5, 1 + 3 i, and
4
+
3
i
4 plus 3 i to represent the vertices of a quadrilateral in the complex number plane. What type of quadrilateral has these vertices?
The multiplicative inverse of a complex number z is
1
z
1 over z where
z
≠
0
.
bold italic z not equal to 0 . Find the multiplicative inverse, or reciprocal, of each complex number. Then use complex conjugates to simplify. Check each answer by multiplying it by the original number.
- 2 + 5 i
-
8
−
12
i
8 minus 12 i
-
a + bi
Find the sum and product of the roots of each equation.
-
x
2
−
2
x
+
3
=
0
x squared , minus 2 x plus 3 equals 0
-
5
x
2
+
2
x
+
1
=
0
5 x squared , plus 2 x plus 1 equals 0
-
−
2
x
2
+
3
x
−
3
=
0
negative 2 , x squared , plus 3 x minus 3 equals 0
For
a
x
2
+
b
x
+
c
=
0
,
bold italic eh , bold italic x squared , plus bold italic b bold italic x plus bold italic c equals 0 comma the sum of the roots is
−
b
a
negative , b over eh and the product of the roots is
c
a
.
c over eh , .
Find a quadratic equation for each pair of roots. Assume a
= 1.
-
−
6
negative 6
i and 6 i
-
2
+
5
i
2 plus 5 i and
2
−
5
i
2 minus 5 i
-
4
−
3
i
4 minus 3 i and
4
+
3
i
4 plus 3 i
Two complex numbers a
+
bi and c
+
di are equal when a
=
c and b
=
d. Solve each equation for x and y.
-
2
x
+
3
y
i
=
−
14
+
9
i
2 x plus 3 y i equals negative 14 plus 9 i
-
3
x
+
19
i
=
16
−
8
y
i
3 x plus 19 i equals 16 minus 8 y i
-
−
14
−
3
i
=
2
x
+
y
i
negative 14 minus 3 i equals 2 x plus y i