-
Physics The formula
F
=
m
v
2
r
f equals . fraction m , v squared , over r end fraction gives the centripetal force F of an object of mass m moving along a circle of radius r, where v is the tangential velocity of the object. Solve the formula for v. Rationalize the denominator.
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Satellites The circular velocity v in miles per hour of a satellite orbiting Earth is given by the formula
v
=
1.24
×
10
12
r
,
v equals . square root of fraction 1.24 , times , 10 to the twelfth , over r end fraction end root . comma where r is the distance in miles from the satellite to the center of the Earth. How much greater is the velocity of a satellite orbiting at an altitude of 100 mi than the velocity of a satellite orbiting at an altitude of 200 mi? (The radius of the Earth is 3950 mi.)
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- Simplify
2
+
3
75
fraction square root of 2 plus square root of 3 , over square root of 75 end fraction by multiplying the numerator and denominator by
75
.
square root of 75 .
- Simplify the expression in (a) by multiplying by
3
square root of 3 instead of
75
.
square root of 75 .
- Explain how you would simplify
2
+
3
98
.
fraction square root of 2 plus square root of 3 , over square root of 98 end fraction . .
Simplify each expression. Rationalize all denominators.
-
5
⋅
50
square root of 5 dot square root of 50
-
4
3
⋅
80
3
cube root of 4 , , dot , cube root of 80 ,
-
x
5
y
5
⋅
3
2
x
7
y
6
square root of x to the fifth , y to the fifth end root . dot 3 . square root of 2 , x to the seventh , y to the sixth end root
-
5
2
x
y
6
⋅
2
2
x
3
y
5 . square root of 2 x , y to the sixth end root . dot 2 . square root of 2 , x cubed , y end root
-
2
(
50
+
7
)
square root of 2 . open , square root of 50 plus 7 , close
-
5
(
5
+
15
)
square root of 5 . open . square root of 5 plus square root of 15 . close
-
5
x
4
2
x
2
y
3
fraction square root of 5 , x to the fourth end root , over square root of 2 , x squared , y cubed end root end fraction
-
5
2
3
7
x
fraction 5 square root of 2 , over 3 , square root of 7 x end root end fraction
-
1
9
x
3
fraction 1 , over cube root of 9 x end root , end fraction
-
10
5
x
2
3
fraction 10 , over cube root of 5 , x squared end root , end fraction
-
14
3
7
x
2
y
3
fraction cube root of 14 , , over cube root of 7 , x squared , y end root , end fraction
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3
11
x
3
y
−
2
12
x
4
y
fraction 3 . square root of 11 , x cubed , y end root , over negative 2 . square root of 12 , x to the fourth , y end root end fraction
-
Physics The mass m of an object is
80
square root of 80 g and its volume V is
5
cm
3
.
square root of 5 , cm cubed . . Use the formula
D
=
m
V
d equals , m over v to find the density D of the object.
-
Writing Does
x
3
=
x
2
3
square root of x cubed end root , equals , cube root of x squared end root , for all, some, or no values of x? Explain.
-
Open-Ended Of the equivalent expressions
2
3
,
2
3
square root of 2 thirds end root , comma , fraction square root of 2 , over square root of 3 end fraction and
6
3
,
fraction square root of 6 , over 3 end fraction , comma which do you prefer to use for finding a decimal approximation with a calculator? Justify your reasoning.
-
Error Analysis Explain the error in this simplification of radical expressions.
Determine whether each expression is always, sometimes, or never a real number. Assume that x can be any real number.
-
−
x
2
3
cube root of negative , x squared end root ,
-
−
x
2
square root of negative , x squared end root
-
−
x
square root of negative x end root
C Challenge
Simplify each expression. Rationalize all denominators.
-
16
x
4
y
4
square root of square root of 16 , x to the fourth , y to the fourth end root end root
-
8000
3
square root of cube root of 8000 , end root
-
y
−
3
x
−
4
6
the sixth , root of fraction y super negative 3 end super , over x super negative 4 end super end fraction end root ,
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Reasoning When
x
a
y
b
square root of x to the eh , y to the b end root simplified, the result is
1
x
c
y
3
d
,
fraction 1 , over x to the c . y super 3 d end super end fraction . comma where c and d are positive integers. Express a in terms of c, and b in terms of d.