-
-
Sketch one cycle of the graph of each cosine function. See Problem 2.
-
y
=
cos
2
θ
y equals cosine 2 theta
-
y
=
−
3
cos
θ
y equals negative 3 cosine theta
-
y
=
−
cos
3
t
y equals negative cosine 3 t
-
y
=
cos
π
2
θ
y equals cosine , pi over 2 , theta
-
y
=
−
cos
π
θ
y equals negative cosine pi theta
Write a cosine function for each description. Assume that
a
>
0
.
eh greater than 0 . See Problem 3.
- amplitude 2, period π
- amplitude
π
2
,
pi over 2 , comma period 3
- amplitude π, period 2
Write an equation of a cosine function for each graph.
-
-
Solve each equation in the interval from 0 to 2π. Round your answer to the nearest hundredth. See Problem 4.
-
cos
2
t
=
1
2
cosine 2 t equals , 1 half
-
20
cos
t
=
−
8
20 cosine t equals negative 8
-
−
2
cos
π
θ
=
0.3
negative 2 cosine pi theta equals 0.3
-
3
cos
t
3
=
2
3 cosine , t over 3 , equals 2
-
cos
1
4
θ
=
1
cosine , 1 fourth , theta equals 1
-
8
cos
π
3
t
=
5
8 cosine , pi over 3 , t equals 5
B Apply
Identify the period, range, and amplitude of each function.
-
y
=
3
cos
θ
y equals 3 cosine theta
-
y
=
−
cos
2
t
y equals negative cosine 2 t
-
y
=
2
cos
1
2
t
y equals 2 cosine . 1 half , t
-
y
=
1
3
cos
θ
2
y equals , 1 third cosine , theta over 2
-
y
=
3
cos
(
−
θ
3
)
y equals 3 cosine . open , negative , theta over 3 , close
-
y
=
−
1
2
cos
3
θ
y equals negative , 1 half cosine 3 theta
-
y
=
16
cos
3
π
2
t
y equals 16 cosine . fraction 3 pi , over 2 end fraction , t
-
y
=
0
.
7
cos
π
t
y equals 0 . 7 cosine pi t
-
Think About a Plan In Buenos Aires, Argentina, the average monthly temperature is highest in January and lowest in July, ranging from 83°F to 57°F. Write a cosine function that models the change in temperature according to the month of the year.
- How can you find the amplitude?
- What part of the problem describes the length of the cycle?
-
Writing Explain how you can apply what you know about solving cosine equations to solving sine equations. Use
−
1
=
6
sin
2
t
negative 1 equals 6 sine 2 t as an example.